2х+3 3. S ·dx (х+1)(x2+4)

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A: To Evaluate: ∫6x-x2dx

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Q: –2x x- -dx x2+e-2r A (x-e-2r) x²+e-2x xp- B -2 (х—е -2) x²+e-2x xp- e -2r dx x²+e-2r x²+e -2x D E)…

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Q: 3x +2 J. - dx. (x² +9)(x– 4)x 10. Find the principal value of

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Q: (1) ਤ + x2 x2 + 3 dx (2) In 2 -e ex 1+e dx x +7 (3) --x-6 dx

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Q: f(x)dx = 2, 5 and 8 f(x)dx = -5, then, 8 f(x)dx = -3

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Q: 2x2-3х-1 -dx (x²+9)(x-5) E. Integrate:

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Q: 1. [(4-x) dx. -2

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Q: sin xV1+ cos 2xdx 6. V1 - sin 2xdx 7. 8. cos' xdx 1+x+x? -dx x² + x3 9. I sin 2x 10. I + sin² x xp-

A: Note: As per company policy we are supposed to solve only one question, So kindly repost the other…

Q: | sin x (3cosx)dx 2: VZ 3x dx V1- x4 3:

A: SOLUTION-

Q: 2 1. x(-x² + 1) dx 16 dx 4x2 2. 3. dx x3/7 -V4x dx 4. 5. . (-2x! – x295) dx

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Q: 1-x 362. dx; u = 3x-x 3x-x'

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Q: 3 y = 2x' + 5x from the point (-2,-26) to the point (4,148), you'd have to compute f(x)dx a

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Q: 8. f sec² (3x - 1) dx

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A: The given function,       y=12.sin θ+2

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Q: 7) x¹ 9-x ² dx X 3 2 2 where u-x ² dv = x √ 9-x² dx 2

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A: the given triple integral is: we have to evaluate the given triple integral.

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Q: Find:  ∫5-9x/ (x-1)(3x-2) dx  where x > 1.

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Q: 2. Evaluate. (Зx* - 2х + 1)dx -2

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A: The given problem is evaluate the given definite integral using Simpsons 3/8 rule.

Q: 3 = 4- 2y + - dx

A: The differential equation is,   The figure below represents the vector field of the differential…

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Q: + 2sin(x) + 7e"dx

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Q: x²-3x+2 5. dx = x-1 1- zero 2- -6 2- -2 4- -8

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Q: 5-7 -1 Using quotient rule, show-that d [cotx] dx 2. 1+x

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Q: (х2-2х+11)dx (x2+3х-4) .2.

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