Question
Asked Dec 28, 2019
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A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are doubled as shown in Figure P12.18. What is the energy absorbed by heat into the gas during this process? Hint: The internal energy of a monatomic ideal gas at pressure P and occupying volume V is given by U = 3/2PV

2Po
Po
2Vo
Vo
Figure P12.18
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2Po Po 2Vo Vo Figure P12.18

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Expert Answer

Step 1

The area under the graph in a PV diagram is equal to the work done on the fluid. If the final volume is greater than the initial volume, then the work done on the fluid is negative. So the work done is

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Step 2

The internal energy of a monatomic ideal gas at pressure P and occupying vo...

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Thermodynamics

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