2t 2t y" + 5y' + 6y = 4te + 4e + 18t + 21 with initial values y(0) = -5 and y' (0) = 18. A. Write the characteristic equation for the associated homogeneous equation. (Use r for your variable.) ^2+5r+6=0 B. Write the fundamental solutions for the associated homogeneous equation. e^(-2*t) Y2 e^(-3*t) C. Write the form of the particular solution and its derivatives. (Use A, B, C, etc. for undetermined coefficients. Y Y' %3D Y" D. Write the general solution. (Use c1 and c2 for c and c2). y = E. Plug in the initial values and solve for c and c2 to find the solution to the initial value problem. y = 3e^(-2*t)-3e^(-3*t)+2t^2e^(-2*t)+3t+1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2t
2t
y" + 5y' + 6y = 4te
+ 4e
+ 18t + 21
with initial values y(0) = -5 and y (0) = 18.
%3D
A. Write the characteristic equation for the associated homogeneous equation. (Use r for your variable.)
*2+5r+6=0
B. Write the fundamental solutions for the associated homogeneous equation.
e^(-2*t)
e^(-3*t)
C. Write the form of the particular solution and its derivatives. (Use A, B, C, etc. for undetermined coefficients.
Y
Y'
%3D
Y"
%3D
D. Write the general solution. (Use c1 and c2 for c and c2).
y =
E. Plug in the initial values and solve for c and c2 to find the solution to the initial value problem.
y = 3e^(-2*t)-3e^(-3*t)+21^2e^(-2*t)+3t+1
Hint: No fractions are required in the solution or answer to this problem.
Transcribed Image Text:2t 2t y" + 5y' + 6y = 4te + 4e + 18t + 21 with initial values y(0) = -5 and y (0) = 18. %3D A. Write the characteristic equation for the associated homogeneous equation. (Use r for your variable.) *2+5r+6=0 B. Write the fundamental solutions for the associated homogeneous equation. e^(-2*t) e^(-3*t) C. Write the form of the particular solution and its derivatives. (Use A, B, C, etc. for undetermined coefficients. Y Y' %3D Y" %3D D. Write the general solution. (Use c1 and c2 for c and c2). y = E. Plug in the initial values and solve for c and c2 to find the solution to the initial value problem. y = 3e^(-2*t)-3e^(-3*t)+21^2e^(-2*t)+3t+1 Hint: No fractions are required in the solution or answer to this problem.
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