2x+1 Let f(x)= 3x-7 4. (a) Find f(x)

Q: G-Xモ-(X))

A: f(x)=2x-5   Replace x = x-5   f(x-5) = 2(x-5)-5 f(x-5) = 2x-10-5 f(x-5) = 2x-15

Q: im ³√2x²-10 x-->3

A: Given : limx-->32x23-10 To find out limit we plug in 3 for x directly inside the cube root

Q: 9) Find f(-2). f(x)=3x2 - 8x + 7 My Answer: 10) Given f(x) = x2 - x³, find f(-10). %3D My Answer:…

A:

Q: 4- f(x) -1 -1+ f(0) f(x) 0 x f '(0) 4. 3.

A:

Q: 6. f(x) =-11x-7x? DEGREE: LEADING COEFFICIENT: END BEHAVIOR: As x 00, y→ As x→-0, y

A:

Q: f(x)= 2x+5 3x-2 -19 (3x-2) f(x)=-

A: SOLUTION-

Q: F(x)=3x^2+2x-4-F(x)=

A: Given:The function is,

Q: 2x2 (b) lim 2x 24 - - x - 4

A:

Q: x²+2x=1 then f'(1) is Let f(x) = 2x3+1

A: we have given f(x). And we have to find f'(1)

Q: 3. Solve f(g(-2)) if f(x): and g(x) = 8 + 5x 3 + 2x

A:

Q: f(x) = 11 - x f-1(2) =

A:

Q: 28. f (x) = 2*-2

A: This is a question on algebraic transformations of functions.

Q: 6. f(x) S(x) =-- x-3

A: Given query is to find domain , vertical asymptot and the intercepts of the function.

Q: f(x)=1-2x What is f(1/x)?

A: Solution: The objective is to find f(1/x)

Q: 33 + 5f(x)+7²(f(x))° = 0 and f(-2) = –1, find f'(-2).

A:

Q: f ''(x) = 8 + 6x + 36x2, f(0) = 5, f (1) = 16

A:

Q: 2х - 2 -1< x<0 f (x) = {-2x – 2 (5 (x+2) 0 <x<1

A:

Q: lim f(x). V5-2x2 <f(x)< V5-x² for -15xs1, find

A: Since both the function lies in interval for x=0. Hence let us find the interval  for the first…

Q: السؤال الثاني |4-x Vx-1 Find the domain of y = - 2 3+x| x+5

A: We have to find the domain of y=4-x3+x-2-x-1x+5 For domain x≠-3, x≠-5 and  x-1≥0⇒x≥1 And…

Q: x2 -x-2 lim 12 x- 2x X-2

A:

Q: 3x2-7x+8 f(x) = Find f'(x) %3D sin (5x2+9x-6)

A: Here we use division rule of differenciation.

Q: Graph each function.

A: The zeros of a function are the point where the function value is equal to 0. These points are also…

Q: 4x+V1-2x 1. f (x) find the domain only. %3D V9-x2

A:

Q: 3 fx} -1 2 4 5 -1 f(0) = 3 f(x) = 0, x = f-'(0) = f-'(x) = 0, x = 3.

A: we have to find the following

Q: 2) f(x) = {*+ 2 , -1<x<0 0 <x <1 2) f(x) = {* +? х,

A:

Q: f(x) = \frac (1) (x+3) f^(-1)(x) = `-

A: topic: function

Q: F(x)=x^2-1 F(-1/7)

A:

Q: f(x) = -x² + ax + b, x < 2 (-ax + 7, x ≥ 2

A: Here we have to find the value of a and b such that,  f(x)=-x2+ax+b, x&lt;2-ax+7, x≥2 is continuous…

Q: f(x)-f(-1) X-1 Where f (x) = 2x-6

A:

Q: 2 4x f(x) = * - 9 I + 2

A:

Q: Lim            [4(2x-1)2-196]/(x+3) x-&gt;-3

A: Given that the limit is

Q: (x² +7x-7)(3x-4) (3x-1)(x²–9) 7. f(x) = Show your solution applying Quotient and product rule 8. у…

A: We have multiple question since our guideline is solve first problem only.

Q: f(x) = (x² + 5x + 2)³ f' (x) = f'(4) = Natu

A: Use differentiation rule to calculate value

Q: Describe the end behavior for this fucntion F(x)=x^5-3x^3+2x-4

A:

Q: 51. f(x) = √2-3x²; f''(x)

A:

Q: f(x) -3x + 5 -3 く x < 0 三 -3 X = 0 -2x

A: The given function is fx=-3x+5    if  -3≤x&lt;0-3            if   x=0-2x         if    x&gt;0.…

Q: 5. f '(x) = 7x + + – x³ find f(x) if f(0) = 7 -

A:

Q: 8. f"(x)= 1 2 f'(-1) = 2; f(-1) = 4 x²

A:

Q: f'(x) = -2xe f"(x) = (4x² – 2)e- f(4) (x) = 4e* f(3) (x) = -4xe-" (2x² – 3) (3 –12x² + 4x*)

A:

Q: Lim 5X-1 - 3 J5メ-1 2. メ→2 8-2X

A: use L'Hospital rule to solve given problem...

Q: x-2, xS-2 3) f(x) = %3D (-x-3, x>-2

A:

Q: 2x-3 5. Let f(x) = find 3x+4 Ax as Ax -0

A:

Q: ) f(x) = V4 - シx-2 x- 2 %3D 1 8) f(x): %3D 9) f(x) = 1 %3D Vlx|-x 1 10) f(x) %3D |x|+x^ 11) f(x) =…

A:

Q: f)-\2+1 x>-5 3x-2 xS-5 find f(-5) and f(3). x +1 x>-5

A: For f(-5)    at x=-5  first function is given so put x=-5  in first function. And for f(3)   it…

Q: First principle of f(x) 6÷x

A:

Q: 4) f(x) = ! g(x) – - - - 3

A:

Q: the intervals where the function is increasing and the interval is decreasing  f(x) = 1/3x^3 - 5x^2…

A:

Q: 2) f(x) = x + 5 glx) = -x - 5x Find f(g(-4))

A:

Q: 5. f(x) = x²(3x + 2)³; f'(-2)

A:

Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.