2x2 - 7 13. lim 5x + x – 3

Q: Vx + 3x² 25. lim 4х - 1

A: We have to find the limit

Q: Evaluate the limit.

A: The given question belonging to the calculus in which we have to find the limiting value of the…

Q: -2х - 4х +4 а. lim х3 — 27 х— 2 b. lim 9x² +1

A: Compute the given limits.

Q: lim, x2+5x-14 x+2

A:

Q: Find the limits by rewriting the fractions first.

A:

Q: V9x* +1 lim .2 x→∞ x² – 3x+5 4 is (A) 1 (B) 3 (C) 9 (D) nonexistent

A:

Q: 6z3 e) lim 10 r2 - 7

A:

Q: D-16 2. Lim Z2-1 / Z2+3Z-1 Z- -16 3. Lim (2w+w? / w²+4

A: y→16limy2-y-2y3-6y2-7y+1 At first we will factorize the numerator and the denominator, but we can…

Q: 4x- x2 5. lim 42-Vx x2 +12 - 4 |6.lim- x- 2 Final Final Answer. Answer:

A: Given:            limx→44x-x22-x Rationalize denominator           =4x-x22-x×2+x2+x=x4-x2+x4-x=x2+x…

Q: 4 2 . 02- 9f 2xS 9x) s X-X+2 lim

A: Given: 2x≤gx≤x4-x2+2

Q: x²-4 (b) lim 4-2 X+2

A: We have to evaluate the limit: blimx→-2x2-4x+2 After putting limit value we get that it is in the…

Q: x5-5x-12 1. lim х—2 х10-500х-24

A:

Q: Determine the following limits or state that they do not exist.

A: x3-5x2+6xx4-4x2

Q: Find the limits

A: Given: limx→-∞2x+4x2+3x-2. for finding this limit we multiply and divide with 2x-4x2+3x-2

Q: 4x3 + 3x2 15) lim 15) x-- 0 x- 5x2 D) - 3 A) o B) – C) 4

A: topic - limits

Q: х2+x-12 9. lim x-3 2x2-7х+3

A: Given: limx→3x2+x-122x2-7x+3 To Find: To evaluate the given limit.

Q: x-16 3. lim エー6 Vx -4

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 9r2 +2r 5 (h) lim 5x +3

A: Topic = Limits As per guidelines , At a time only one question can be answered. please repost for…

Q: ■ Find the limit.

A: Evaluate limx→∞3x-22x+1

Q: 24. lim 4- 2x x-2

A:

Q: (i) Lim   5x -3  - 4     x→∞  2x -2 + 9

A:

Q: x - 4 t2 + 2 24. lim 13 + t2 - 1

A:

Q: 22-3r 10 d) lim z5 r2 -r - 20

A:

Q: 7x3 – 4x + 2x6 lim с. 5x3 — Зх2 x--00 7x3 - 4x + 2x6 lim d. 5x9 — Зх2 x00 7x3 - 4x + 2x lim 5x3 —…

A:

Q: 22-7x 18 lim r -2 x + 2

A: Consider the following limit:…

Q: (4x-V16x C. lim +3x-5 3x-7* d. lim x0 2x-15*

A: c)…

Q: Vx2-7х+16-у6 2. lim X→5 (х-5)/x+1

A:

Q: .3 5x* + 2х -1 3. Find lim .3 Зx* +5х—7

A: We need to take common highest degree from numerator and denominator

Q: 5x?-4х 4. lim- x+0 2x2+3 5. limVx6 + 5х3 — х3 3 2+3x-5x2 6. lim 1+8x2

A: This question is related to limit.solved in step 2.

Q: x3-3x+2 lim-1 (x-1)2 12 15 18 O 3 6.

A:

Q: a +b° + c° limy- 3 8.

A: the given limit is ,                     lim(x→∞ax+bx+cx3)1x in order to find the limit first take…

Q: y + 6 21. lim ソ→6+ y2- 36

A:

Q: lim (9x* — 2а* + 7a — 5)

A:

Q: 2. 3X+ 15X +18 lim X→-2 X2+X-2

A: Given that limx→-23x2+15x+18x2+x-2…

Q: Vz - 3 lim z-3 z2- 9

A: We know,  limx→af(x)=f(a) a2-b2=(a-b)*(a+b)

Q: Vx2 -25 b) lim x→-0o 6x-18

A: We have to find the limit

Q: (x2-5х -9 20. lim 2x4+3x А. 2 В. О С. о D. -00

A: Let L is the value of given Limit.

Q: 5a - 4x + x (a) lim 376 + 6x? t2 + 21 – 3 (b) lim 1 t2 – 3t + 2 23+2 (c) lim 3+3

A:

Q: 2+3t+2 lim -1 2-t-2 (ii).

A: Given limit: limt→-1 t2+3t+2t2-t-2

Q: Find the limit

A:

Q: x1メーコ| 7) tim メ3 x2-9 2\ 8) lim 2X- X-15 メマ メ)x-3|

A: 1. limx→3-xx-3x2-9 x-3=-x+3 as x→3- and x2-9=(x+3)(x-3)…

Q: 2x 2x2 8. lim X-1 x+1

A: We will find the limit.

Q: lim 2V3. +onx 2cosx+1 %3D 6.

A: Our Aim is to evaluate limx→π623×tanx2 cosx+1 -(i)

Q: x²+9x+20 1. lim x→-4 x²-16 I|

A:

Q: 1) 2|3x + 9| < 36 x2-2 2) lim х-2 х-3х+2

A: According to question given that :(1)   23x+9&lt;36(2)   limx=2x2-23x+2

Q: 3x 2х 2) Lim х-1 х+1° X → 00

A: Given,   limx→∞(3xx-1-2xx+1)

Q: 9x2-7x+6 lim I 10z z+10 Evaluate: %3D

A:

Q: 3) lim (x- 3x + 4) 4) lim -V2x-2 A) -5 C) 0 B) 2 D) 7 A) V12 C) 2 B) -7 D) -6

A: 3.

Q: C. lim (4x xx-√16x² + 3x - 5) X→∞

A: Given limits, (c) limx→∞4x-16x2+3x-5 (d) limx→03x-7x2x-15x We have to find the Limit of the given…

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.