3 9 12 15 ListB з | 4 1 2 Based on above memory illustrations. Complete these following fragment code : (i), (ii), (iii) Hint : Array ListB is the manipulation of array ListA. int ListA[5] = // (i) initialization of array ListA int ListB[5]; for( int i = 0; ; i++){ //(ii) control expression for maximum index ListB[i] = ;//(ii) manipulate elements in ListA to save in ListB cost < [> }

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
3
6.
9
12
15
ListB
1
2
3
Based on above memory illustrations. Complete these following fragment code: (i), (ii), (iii)
Hint : Array ListB is the manipulation of array ListA.
int ListA[5] =
// (i) initialization of array ListA
int ListB[5];
for( int i = 0;
i++){ //(ii) control expression for maximum index
ListB[i] =
;//(ii) manipulate elements
ListA to save in ListB
cost < [>
}
Transcribed Image Text:3 6. 9 12 15 ListB 1 2 3 Based on above memory illustrations. Complete these following fragment code: (i), (ii), (iii) Hint : Array ListB is the manipulation of array ListA. int ListA[5] = // (i) initialization of array ListA int ListB[5]; for( int i = 0; i++){ //(ii) control expression for maximum index ListB[i] = ;//(ii) manipulate elements ListA to save in ListB cost < [> }
A.
(i) [ 3,6,9,12,15];
(ii) i< =4;
(iii) ListA [i] /3;
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA / 3;
C.
(i) { 3,6,9,12,15};
(ii) i < 5;
(iii) ListA [i] /3;
D.
(i) { 3,6,9,12,15}
(ii) i < 5;
(iii) ListB /3;
B.
Transcribed Image Text:A. (i) [ 3,6,9,12,15]; (ii) i< =4; (iii) ListA [i] /3; (i) { 3,6,9,12,15}; (ii) i < 5; (iii) ListA / 3; C. (i) { 3,6,9,12,15}; (ii) i < 5; (iii) ListA [i] /3; D. (i) { 3,6,9,12,15} (ii) i < 5; (iii) ListB /3; B.
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