3) Consider the differential equation (5y³ – 5x)dx – 15xy?dy = 0 In order for the expression 5y3 = kæ In(x) + Cx %3D where k is a parameter and C is a constant, be the general solution of the differential equation the value of the parameter k must be: a) k= 5 b) k = 10 c) k = –15 |

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