3) GIVEN : 2 CW Pumps Total Power Drawn = 2261 KW Percent Improvement in Power Consumption = 4.5% Running Hours = 3000 Hrs Electricity Rate = Php 3.01/KWh Find : (a) Expected power after improvement in efficiency in KW. (b) Power saving in KW. (c) Energy saving (Units) (d) Cost of energy saving (e) Payback period.

3) GIVEN : 2 CW Pumps Total Power Drawn = 2261 KW Percent Improvement in Power Consumption = 4.5% Running Hours = 3000 Hrs Electricity Rate = Php 3.01/KWh Find : (a) Expected power after improvement in efficiency in KW. (b) Power saving in KW. (c) Energy saving (Units) (d) Cost of energy saving (e) Payback period.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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