3 Practice Problem AG° = -RT ln(K) What is the thermodynamic equilibrium constant expression, K, for the reaction below? CaCO3(s) CaO(s) + CO₂(g) -1128.8. -603.5 -394.4 Use the data below to calculate the K at 25 °C for the reaction Substance AG, (kJ/mol) at 25 °C K= 1.1679 X 10-23 CaCO3(s) -1128.8 CaO(s) -603.5 Spontaneous @OK CO₂(g) -394.4 AG=-

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