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3. A COMBINATIONAL CIRCUIT IS DEFINED BY THE FOLLOWING THREE BOOLEAN FUNCTIONS. DESIGN THE CIRCUIT WITH A DECODER AND EXTERNAL GATES
- F1= X'Y'Z' + XZ
- F2= XY'Z' + X'Y
- F3= X'Y'Z + XY
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- A combinational circuit is defined by the following three Boolean functions. Design the circuit with a decoder and external gates. F1 = x' y' z' + xzF2 = x y' z' + x'yF3 = x' y' z + xyWrite the three outputs of X, Y and Z in terms of the four inputs A, B, C and D for the follow logic gates configuration ---This is my answer: I am unsure if it is right. X = A + (A’B’ * (B’+C’) = A + (A’+B’)*(B’*C’) Y = ((A’+B’)*(B’*C’))*((B’*C’)+CD)Z = (B+C)*(C’+D’)*D’Design a combinational circuit with three inputs, x , y , and z , and three outputs, A, B, and C . When the binary input is 0, 1, 2, or 3, the binary output is two greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input.
- Design a combinational circuit with three inputs A, B, & C. The output Z is HIGH when the binary value of the inputs is an EVEN number and is greater than TWO. Draw the circuit using ONLY NOR gates.Design a combinational circuit with three inputs x, y, and z and three outputs A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input.A 1bit 4 to 1 multiplexer, the 4 inputs of the multiplexer will be the output of another combinational circuit with A and B as an input:00 = 1bit Adder01 = 1bit Subtractor10 = 1bit Comparator (equals)11 = XOR • truth table• Boolean Expression• Logic Circuit Here is the truth table guide:
- Design a combinational logic circuit that takes a 3–bit input and has one output P. The P output should be active high only when the inputs corresponds to a prime number Note: the prime numbers: Prime numbers are 2, 3, 5, 7… Select one: a. P= AC+B b. P= A'C+A'B c. P= AC+A'B d. P= AC+A'B'Design a combinational circuit with three inputs x, y, z, and three outputs a, b, and c. When the binary input is 0, 1,2, or 3 , the binary output is 1 greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is one less than the input.Use Boolean algebra to simplify the following expression, then draw a logic gate circuit for the simplified expression: A’B’C’+A’B’C+AB’C’+AB’C
- Using a decoder and external gates, design the combinational circuit defined by the following three Boolean functions:1. (a) F 1 = x ′ y z ′ + x z F 2 = x y ′ z ′ + x ′ y F 3 = x ′ y ′ z ′ + x y2. (b) F 1 = ( y ′ + x ) z F 2 = y ′ z ′ + x ′ y + y z ′ F 3 = ( x + y ) zGiven a 4-bit signed integer, design a circuit that outputs its absolute value. You can assume that the input will always have a valid output. (a) Draw a logic diagram of this circuit. You may use 4-bit half adder(s), 2x1 4-bit multiplexer(s), and any logic gate(s) in your design. (b) With the following Verilog code, implement your design above in Verilog. module half_adder (input [3:0] a, input [3:0] b, output [3:0] s); assign s = a + b; endmodule module mux(input [3:0] D0, input [3:0] D1, input S, output reg [3:0] O); always @(*) begin if (S == 0) O = D0; else if (S == 1) O = D1; else O = 4’bx; end endmoduleWrite the Boolean expression (in Sum of Products form) for the logic circuit that will have a 1 output when X = 0, Y = 0, Z = 1 and X = 1, Y = 1, Z = 0, and a zero (0) output for all other input states. Draw the logic diagram for this circuit.