3. (a) Solve the given differential equation y" + 4y = (x² – 3) sin 2a.

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3. (a) Solve the given differential equation
y" + 4y = (x² – 3) sin 2r.
(b) Without solving. What is the form of a particular solution of
y" + y = x3 + 2+ cos 2x.
Transcribed Image Text:3. (a) Solve the given differential equation y" + 4y = (x² – 3) sin 2r. (b) Without solving. What is the form of a particular solution of y" + y = x3 + 2+ cos 2x.
Expert Solution
Solution:

The differential equation is y''+4y=x2-3sin2x.

Obtain the homogeneous solution of y''+4y=0 as yhx=c1cos2x+c2sin2x

Consider the particular solution as ypx=Ax2+Bx+Csin2x.

Then

yp'x=2Ax2+Bx+Ccos2x+2Ax+Bsin2xyp''x=-4Ax2+Bx+Csin2x+22Ax+Bcos2x+22Ax+Bcos2x+2Asin2x=-4Ax2+Bx+C+2Asin2x+42Ax+Bcos2x

Substitute the results:

 

So we have

-4Ax2+Bx+C+2Asin2x+42Ax+Bcos2x+4Ax2+Bx+Csin2x=x2-3sin2x2Asin2x=x2-3sin2xA=-32, and we can consider B=0 and C=-3

Hence, the particular solution is ypx=-32x2-3sin2x

Therefore, the general solution is yx=yhx++ypx=c1cos2x+c2sin2x+-32x2-3sin2x.

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