3. Draw the 'H NMR spectrum that you would expect to see for glucose in the anomeric region (considering that a sample of glucose, dissolved in water at room temperature and allowed to come to equilibrium, consists of a mixture of alpha and beta forms in a ratio of approximately 40:60). Assume that the chemical shift for a proton in the axial position is expected to have a somewhat lower chemical shift than a proton in an equatorial position.* (Anomeric region will be roughly 4.5-5.5 ppm) 6.0 5.0 4.0

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Chapter1: Chemical Foundations
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3. Draw the 'H NMR spectrum that you would expect to see for glucose in the
anomeric region (considering that a sample of glucose, dissolved in water at room
temperature and allowed to come to equilibrium, consists of a mixture of alpha and
beta forms in a ratio of approximately 40:60). Assume that the chemical shift for a
proton in the axial position is expected to have a somewhat lower chemical shift
than a proton in an equatorial position.* (Anomeric region will be roughly 4.5-5.5
ppm)
6.0
5.0
4.0
Transcribed Image Text:3. Draw the 'H NMR spectrum that you would expect to see for glucose in the anomeric region (considering that a sample of glucose, dissolved in water at room temperature and allowed to come to equilibrium, consists of a mixture of alpha and beta forms in a ratio of approximately 40:60). Assume that the chemical shift for a proton in the axial position is expected to have a somewhat lower chemical shift than a proton in an equatorial position.* (Anomeric region will be roughly 4.5-5.5 ppm) 6.0 5.0 4.0
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