3. Gold is very valuable because it does not oxidize easily. It can be oxidized by reacting it with nitric acid as shown below: Au(s) + 4H (aq) + NO: (aq) → NO(g) + 2H:0(g) + Au³ (aq) 3a. If 30 grams of gold react with 3.4 grams of nitrate ion, which reactant is limiting?

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Honors Chemistry
Chapter 9
Name/Date
3. Gold is very valuable because it does not oxidize easily. It can be oxidized by reacting it with nitric acid as shown
below:
Au(s) + 4H'(aq) + NO: (aq) → NO(g) + 2H:0(g) + Au³ (aq)
3a. If 30 grams of gold react with 3.4 grams of nitrate ion, which reactant is limiting?.
3b. What is the theoretical yield?.
4. Lead (II) nitrate reacts with sodium chloride according to the equation below:
Pb(NO.): + NaCl → PbCla + NANO.
4a. If 8.3 grams of lead (II) nitrate react with 5 grams of sodium chloride, which material would be the limiting
reactant?
4b. What is the theoretical yield?
Transcribed Image Text:Honors Chemistry Chapter 9 Name/Date 3. Gold is very valuable because it does not oxidize easily. It can be oxidized by reacting it with nitric acid as shown below: Au(s) + 4H'(aq) + NO: (aq) → NO(g) + 2H:0(g) + Au³ (aq) 3a. If 30 grams of gold react with 3.4 grams of nitrate ion, which reactant is limiting?. 3b. What is the theoretical yield?. 4. Lead (II) nitrate reacts with sodium chloride according to the equation below: Pb(NO.): + NaCl → PbCla + NANO. 4a. If 8.3 grams of lead (II) nitrate react with 5 grams of sodium chloride, which material would be the limiting reactant? 4b. What is the theoretical yield?
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