There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide water react to form acetylene and calcium hydroxide: CaC2(s) + 2 H,O(g) → C,H,(g) + Ca(OH),(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6 C,H,(9) + 3 C0,(9) + 4 H,O(g) - 5 CH,CHCO,H(g) AH=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reaction. Round your answer to the nearest kJ.

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Chapter3: Mass Relations In Chemistry; Stoichiometry
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and
water react to form acetylene and calcium hydroxide:
CaC(s) + 2 H,O(g) → C,H;(g) + Ca(OH),(s)
AH=-414. kJ
In the second step, acetylene, carbon dioxide and water react to form acrylic acid:
6C,H2(9) + 3 CO,(9) + 4 H,O(9)
- 5 CH,CHCO,H(9)
AH = 132. kJ
Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions.
Round your answer to the nearest kJ.
nue
Transcribed Image Text:3. 4 6. 7. 10 There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC(s) + 2 H,O(g) → C,H;(g) + Ca(OH),(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C,H2(9) + 3 CO,(9) + 4 H,O(9) - 5 CH,CHCO,H(9) AH = 132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. nue
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