3. The average monthly payment of a house insurance policy is 2738. This is estimated by using a sample having 45 insurance policies. Also, the sample standard deviation is 65$. (a) For the 95% confidence, compute the margin of error for as point estimate to population mean. (b) Determine the 95% confidence interval estimate of the population mean.

Q: 3. Compute for the sample size if the margin of error is 12, with a sample standard deviation of 35…

A: The z-critical value for a 95% confidence interval is calculated using the excel formula…

Q: Suppose, according to a 1990 demographic report, the average U. S. household spends $90 per day.…

A: Sample mean = $84.5.Sample standard deviation, s is $14.5.The sample size, n is 30.

Q: Suppose the mean​ per-person check for brunch at a restaurant chain is approximately ​$13.75.…

A: The formula for the sample size needed to estimate a population mean is

Q: Suppose you observe 77 data points from a distribution with standard deviation 8.4, and you…

A: Given that,  σ=8.4,n=77 Critical values: By using the z-table, the critical value at 92% confidence…

Q: Suppose that the amount of time spend by working student weekly is normally distributed with the…

A: Given,   Sample size = 120 Sample mean = 150 Population standard deviation = 25   Since the…

Q: A sample of 49 managers reveals a sample mean of $45,420. The standard deviation of the samp is…

A: As the population standard deviation is not known, we will use t-distribution. The number of degrees…

Q: What is the minimum sample size required to estimate a population mean with 95% confidence when the…

A: We have given that,  Margin of error (E) = 1.6 and population standard deviation (σ) = 10.65 and…

Q: 3 In a large city the distribution of incomes per family has a standard deviation of $5200. (i) For…

A: According to central limit theorem, if the population is normally distributed or sample size is at…

Q: In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta…

A: From the provided information, Sample size (n) = 49 Sample mean (x̅) = $24.80 Population standard…

Q: An advertising executive wants to estimate the mean weekly amount of time consumers spend watching…

A:

Q: A motor club wishes to estimate, to within five cents, the mean price of a gallon of gasoline in a…

A: Given information: A motor club wishes to estimate to within five cents. ME=5 Population standard…

Q: The mean for the verbal component of the SAT is reported as 500, with a standard deviation of 100. A…

A: It is given that the sample mean is 498 and the population standard deviation is 100.

Q: What is the minimum sample size required to estimate a population mean with 95% confidence when the…

A: Given, standard deviation, σ = 10.75 margin of error, E = 1.9

Q: Suppose the math department chair at a large state university wants to estimate the average overall…

A: Since, standard deviation is known the critical value at 90% confidence level from the standard…

Q: If the manager of a bottled water distributor wants to estimate, with 95% confidence, the mean…

A:

Q: Suppose the mean​ per-person check for brunch at a restaurant chain is approximately $13.75.     c.…

A: Given Data : Margin of error, ME = 0.25 population standard deviation, σ =…

Q: ) In a study, it was estimated that the average annual expenditure on take-out was Php 75000 for…

A: It is been asked to find if large sample size is required if margin of error increases and the…

Q: 7. A researcher wants to estimate the mean income of all physicians in a city at a 95% confidence…

A: Given,standard deviation(σ)=17500margin of error(E)=5000α=1-0.95=0.05α2=0.025Z0.025=1.96    (from…

Q: If the manager of a bottled water distributor wants to​ estimate, with 99​% ​confidence, the mean…

A:

Q: The Indian River County Health Department needs to estimate the proportion of county residents with…

A: It is given that the sample size (n) is 1507 and x is 672.

Q: 1. Suppose that we want to estimate to within $1000 the mean salary of all graduates who were…

A: Given,margin of error(E)=1000standard deviation(σ)=5000α=1-0.95=0.05α2=0.025z0.025=1.96

Q: What sample size would be needed to estimate the average body temperature of humans if you wished to…

A: Given data,E=0.1z-value at 99% confidence is Zc=2.576σ=0.6n=?

Q: 1. The average height of the students in a famous college in the city is unknown but the standard…

A: 1. The population standard deviation is 0.8, sample size is 49, and sample mean is 6.1. Computation…

Q: In a random sample of six ​people, the mean driving distance to work was 23.2 miles and the standard…

A: We have given that  Sample size n =6 Sample mean = 23.2 Standard deviation =6.4

Q: In a random sample of ten ​people, the mean driving distance to work was 23.2 miles and the standard…

A: Provided information is ; Sample size(n) =10  Mean(μ) = 23.2 Sample standard deviation(s) = 5.3…

Q: The sample size needed to estimate a population mean within 2 units with a 95% confidence when the…

A: Given,σ=8E=2Zc at 95% confidence is Zc=1.96n=?

Q: In a random sample of 8 cell​ phones, the mean full retail price was $539.00 and the standard…

A: From the available information,   The confidence interval is, C=90%=90/100=0.90 The level of…

Q: In a study, it was estimated that the average annual expenditure on take-outwas Php 75000 for…

A: The 95% confidence interval for the population mean amount spent on take-aways, will signify that,…

Q: To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19…

A:

Q: An advertising executive wants to estimate the mean weekly amount of time consumers spend watching…

A: Given information- Population standard deviation (σ) = 25 minutes Error (E) = 5 minutes The margin…

Q: An advertising executive wants to estimate the mean weekly amount of time consumers spend watching…

A:

Q: 2.The administration at a college wishes to estimate, the proportion of all its entering freshmen…

A: Given;margin of error(E) = 4population standard deviation(σ)= 1.3for confidence level 95%,…

Q: In an effort to estimate the mean dollars spent per visit by customers of a food store, the manager…

A: Given: s = $12.30  n = 100

Q: 1. The mean number of hours of flying time for pilots at Continental Airlines is 49 hours per month…

A:

Q: An advertising executive wants to estimate the mean weekly amount of time consumers spend watching…

A:

Q: blood pressure. A health department researcher found that 634 out of a random sample of 1713 county…

A: We have given that, Favorable cases (X) = 634 and sample size (n) = 1713

Q: The graphic in Question 1 includes the statement "accurate to within +/- 2.9 percentage points, 19…

A: It is given that accurate to within (margin error) 2.9 percentage points, 19 times out of 20. Data…

Q: Find the error bound for an unknown population mean or the margin of error that corresponds to a 85%…

A: Find the error bound for an unknown population mean or the margin of error that corresponds to a 85%…

Q: A sample of 256 managers reveals a sample mean of $45,420. The standard deviation of the sample is…

A: Given: A sample of 256 managers has a sample mean of $45,420 and a standard deviation of $2,050.…

Q: ne hundred (900) high school freshmen were randomly selected for a national survey. Among survey…

A: Given data,Mean x=2.7sd     σ=0.4n=900What is the margin of error at 95% confidence level?

Q: When the population standard deviation is unknown and the sample size is greater than 30, what table…

A: It is clear that the population standard deviation is unknown and the sample size is greater than…

Q: If the manager of a bottled water distributor wants to estimate, with 95% confidence, the mean…

A: From the provided information, Standard deviation (σ) = 0.04 Confidence level = 95%

Q: A random sample of 16 employees taken from the management level of the company gives a mean monthly…

A: Given that  Sample size = 16 , Mean = 17000 , Standard deviation = 5500

Q: The following sample data are from a normal population:    Sample size (n) = 25, Sample mean=14,…

A: Given Information: Sample size (n) = 25 Sample mean (x ) = 14 Sample standard deviation (s) = 3.6…

Q: The Martin County Health Department needs to estimate the proportion of county residents with high…

A: Given information We have given that; a health department researcher found that 221 out of a random…

Q: Assume that all grade-point averages are to be standardized on a scale between 0 and 4. How many…

A: Given : Margin of error, ME = 0.007 population standard deviation, σ = 1.0…

Q: 1. The quality control manager at a light bulb factory needs to estimate the mean life of a new type…

A: As per our guidelines we are suppose to do only one questionGivensample size(n)=32sample…

Q: If  the inspection division of a county weights and measures department wants to estimate the…

A: Solution: Given information: Margin of error = E= 0.01  liters Population standard deviation= σ=…

Q: Consider population data with 5 being the standard deviation, 5 being the mean. Compute an 88.9%…

A: It is given that the mean is 5 and the standard deviation is 5.

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.