3. Write a computer program to solve the quadratic equation below: ax²+ bx + c = 0 The input data is to consist of the values of a, b and c and is to come from the keyboard. The output is to consist of the values of x and display to the user. However, your computer must consider all the possibilities, if b?– 4ac is positive, then equation (1.1 and 1.2) can be used directly to find the solutions x1 and x2. However, if the b2 – 4ac is negative, the equation become as in 1.3 and 1.4. Below are the equations. -b+ Jb? – 4ac (3.1) 2a -b- \b² – 4ac (3.2) 2a V- (b² – 4ac) (3.3) X = 2a %3D 2a - b X2 (b² – 4ac) (3.4) 2a 2a

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Write a C program
3. Write a computer program to solve the quadratic equation below:
ax?+ bx + c = 0
The input data is to consist of the values of a, b and c and is to come from the keyboard.
The output is to consist of the values of x and display to the user. However, your computer
must consider all the possibilities, if b?– 4ac is positive, then equation (1.1 and 1.2) can be
used directly to find the solutions x1 and x2. However, if the b? – 4ac is negative, the
equation become as in 1.3 and 1.4. Below are the equations.
-b + \b? – 4ac
(3.1)
2a
-b- Jb? – 4ac
X2
(3.2)
2a
-b V-(b² – 4ac)
(3.3)
2a
2a
-b
X2
(Ь? — 4ас)
(3.4)
2a
2a
Sample of the output show as below:
Enter the values of a, b and c (each separated by a space) then press
enter
15 -2 3
Imaginary result:
x1 - 0.06667 + 0.44222
x2 = 0.06667 - 0.44222
Hint: Use include <math.h> to include sqrt function.
Example: root=sqrt(x);
II
Transcribed Image Text:3. Write a computer program to solve the quadratic equation below: ax?+ bx + c = 0 The input data is to consist of the values of a, b and c and is to come from the keyboard. The output is to consist of the values of x and display to the user. However, your computer must consider all the possibilities, if b?– 4ac is positive, then equation (1.1 and 1.2) can be used directly to find the solutions x1 and x2. However, if the b? – 4ac is negative, the equation become as in 1.3 and 1.4. Below are the equations. -b + \b? – 4ac (3.1) 2a -b- Jb? – 4ac X2 (3.2) 2a -b V-(b² – 4ac) (3.3) 2a 2a -b X2 (Ь? — 4ас) (3.4) 2a 2a Sample of the output show as below: Enter the values of a, b and c (each separated by a space) then press enter 15 -2 3 Imaginary result: x1 - 0.06667 + 0.44222 x2 = 0.06667 - 0.44222 Hint: Use include <math.h> to include sqrt function. Example: root=sqrt(x); II
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