3. - y = 5 with zero initial conditions (i.e. y(0) dy(0) = dt dºy(0) 'y(0) -0) %3D %3D Answer: y(t) = je-t + fe' + cos t – 5

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A:

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A: since we know that L[y''] = p2Y(s)-py(0)-y(0)

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Q: (1+ex/y)dx + ex/y(1-x/y)dy = 0, a exact differential equation? If yes then, find the value of y.

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