Question
Asked Oct 2, 2019
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Can you help me with this problem step by step?

3.7.29
y
If x3 y3 16, find the value of
at the point (2,2)
dx'
X
2y
at the point (2,2) is
2
dx
The value of
(Type a simplified fraction.)
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3.7.29 y If x3 y3 16, find the value of at the point (2,2) dx' X 2y at the point (2,2) is 2 dx The value of (Type a simplified fraction.)

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Expert Answer

Step 1

Given function is

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= 16... ...(i) And x-2, y 2

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Step 2

Differentiate equation (i)

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3x3 +3у? — ..... ....i)

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Step 3

Again differentiate ...

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d'y 0.. dx dy(dy 6x+6y dxdx

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Tagged in

Math

Calculus

Differential Equations