31) For the reaction: PC13(g) + Cl2(g) = PC15(g) at 70.5°C, Kp = 1.05. If one starts with 1.80 atm pressure of PCI3(g), 1.72 atm pressure of Cl2(g), and no PCI5(g), what is the partia pressure of PCI5(g) at equilibrium? A) 0.599 atm B) 0.827 atm C) 0.818 atm D) 0.856 atm E) 0.080 atm

Chemistry: An Atoms First Approach
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Chapter16: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 83AE: Consider the following system at equilibrium at 25C: PCl3(g)+Cl(g)PCl5(g)G=92.50KJ What will happen...
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31) For the reaction:
PC13(g) + Cl2(g) = PC15(g) at 70.5°C, Kp = 1.05.
If one starts with 1.80 atm pressure of PCI3(g), 1.72 atm pressure of Cl2(g), and no PCI5(g), what is the partia
pressure of PCI5(g) at equilibrium?
A) 0.599 atm
B) 0.827 atm
C) 0.818 atm
D) 0.856 atm
E) 0.080 atm
Transcribed Image Text:31) For the reaction: PC13(g) + Cl2(g) = PC15(g) at 70.5°C, Kp = 1.05. If one starts with 1.80 atm pressure of PCI3(g), 1.72 atm pressure of Cl2(g), and no PCI5(g), what is the partia pressure of PCI5(g) at equilibrium? A) 0.599 atm B) 0.827 atm C) 0.818 atm D) 0.856 atm E) 0.080 atm
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