3–4. Designer functions Sketch the graph of a function continuous on the given interval that satisfies the following conditions. 3. f is continuous on the interval [–4, 4]:f'(x) = 0 for x = -2, 0, and 3; f has an absolute minimum at x = 3;f has a local mini- mum at x = -2; f has a local maximum at x = 0;f has an abso- lute maximum at x = -4. %3D 4. f is continuous on (-0, 0); f'(x) < 0 and f"(x) < 0 on (-x, 0);f'(x) > 0 and f"(x) > 0 on (0, 0).
3–4. Designer functions Sketch the graph of a function continuous on the given interval that satisfies the following conditions. 3. f is continuous on the interval [–4, 4]:f'(x) = 0 for x = -2, 0, and 3; f has an absolute minimum at x = 3;f has a local mini- mum at x = -2; f has a local maximum at x = 0;f has an abso- lute maximum at x = -4. %3D 4. f is continuous on (-0, 0); f'(x) < 0 and f"(x) < 0 on (-x, 0);f'(x) > 0 and f"(x) > 0 on (0, 0).
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 99E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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![3–4. Designer functions Sketch the graph of a function continuous on
the given interval that satisfies the following conditions.
3. f is continuous on the interval [–4, 4]:f'(x) = 0 for x = -2,
0, and 3; f has an absolute minimum at x = 3;f has a local mini-
mum at x = -2; f has a local maximum at x = 0;f has an abso-
lute maximum at x = -4.
%3D
4. f is continuous on (-0, 0); f'(x) < 0 and f"(x) < 0 on
(-x, 0);f'(x) > 0 and f"(x) > 0 on (0, 0).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc69a8700-bb74-46a1-b7ab-13455209326c%2F72cdf4d6-47fd-46e9-82ca-a579efa9ea92%2F7x5dxxf_processed.png&w=3840&q=75)
Transcribed Image Text:3–4. Designer functions Sketch the graph of a function continuous on
the given interval that satisfies the following conditions.
3. f is continuous on the interval [–4, 4]:f'(x) = 0 for x = -2,
0, and 3; f has an absolute minimum at x = 3;f has a local mini-
mum at x = -2; f has a local maximum at x = 0;f has an abso-
lute maximum at x = -4.
%3D
4. f is continuous on (-0, 0); f'(x) < 0 and f"(x) < 0 on
(-x, 0);f'(x) > 0 and f"(x) > 0 on (0, 0).
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