340 65 Solve for x and round to the nearest tenth. Show ALL work necessary in the box provided below.

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 19 690 -0

A:

Q: Solve for x. Round to the nearest tenth, if necessary. U 67 42° V

A: The given triangle has UT=67, UV=x and measure of V=42 degree.

Q: Solve for x in the triangle. Round your answer to the nearest tenth. %3D 200 8

A:

Q: . Solve for x in the triangle below. Round your inswer to the nearest tenth.

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Q: X4- Usr Newton Barkweerd poty nomoil to find Fco.73) fx) 0.423 1.03 t5ち子 1789.

A: Given the table of values x 0.4 0.6 0.8 1 fx 0.423 0.684 1.03 1.557

Q: 4. Solve for x on the triangle below. 4cm 45°

A: To find the value of x from the given right triangle

Q: Solve for x in the triangle. Round your answer to the nearest tenth. x = 32

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Q: ナ+sy'+by =4et も

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Q: Solve for x in the triangle. Round your answer to the nearest tenth. I1 68°

A: We will find value of x with the help of trigonometry functions.

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 20°

A: the solution is :

Q: Solve for x.Round to the neares tanth of a dcaree, If necekary 42

A:

Q: Solve 52x – 4(5*) 3 12. Round answer(s) to the nearest tenth, if necessary.

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Q: 63° 16

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Q: Solve for x. Round to the nearest tenth of a degree, if necessary K 27 to 48 J

A: Apply tan(x)

Q: Solve for r. Round to the nearest tenth, if necessary. 26 1.2 Answer: Z Submit Answur attempe i out…

A:

Q: Solve for x. Round to the nearest degree. 50 14

A: We use trigonometric ratio to find the value of x

Q: Solve for x. Round to the nearest tenth, if necessary. U 3-7 T \61° S

A: We have to find the value of x in the given right-triangle STU.

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 40° X -0 X = X

A:

Q: Solve for x. Round to the nearest tenth, if necessary. K 630 1 I

A: given,

Q: Solve for x. Round to the nearest degree. 80 74

A:

Q: Solve for x. Round to the nearest tenth, if necessary. 17° 4.5

A: We have to find x

Q: Solve 6a*tt=5s for X ニ

A: take log in both sides

Q: Solve for x. Round to the nearest tenth of a degree, if necessary. 5.4 4.8

A:

Q: Solve for mZB. Round to the nearest tenth of a degree, if necessary. C 3/3 6. 30° 90° 60° 45° 2 51'F

A: We have to find

Q: Solve for x In the triangle. Round your answer to the nearest tenth. 19 x = 0 550

A:

Q: Solve for x. Round to the nearest tenth, if necessary. S. 27 18°

A: By using properties of triangle.

Q: Solve for æ. Round to the nearest tenth of a degree, necessary. if I 9.1 4.6 H.

A: Given:  To Find: To solve for x.

Q: Solve for x. Round to the nearest tenth, if necessary.- M. J' 18 K 8

A:

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 25° 8 x = 0 X

A:

Q: Solve for r. Round to the nearest tenth of a degree, if necessary. 6.5 U 8.9

A: A triangle is a polygon having three sides and three vertices. Sum of interior angles of triangle is…

Q: Solve for x. Round to the nearest tenth, if necessary. 3.2 23° E

A: In this question, find the value of x when the triangle is given as a right triangle. Using the…

Q: use Suler thod to solve هراد5 me

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Q: 43 29 to Solve for x and round to the nearest tenth. Show ALL work necessary in the box provided…

A:

Q: 13 3 A 3 B D

A: Let angle ∠CAB=θ We know that, tanθ=perpendicular sideadjacent side In right angled △ABC.…

Q: olve accordingly

A: we can see that the graph touches at 4 places on the x-axis.

Q: 20 52°

A: From the given right angled triangle, tan52°=x20    ⇒x=20×tan52°           =25.6 unit

Q: Solve for x. Round to the nearest tenth, if necessary. 7 C 9.

A:

Q: 4. Use the Pythagorean theorem to solve for x. Leave your answers in radical form 10 cm 4 cm 16 ft…

A: We know the Pythagorean theorem states that the sum of squares of sides is equal to hypotenuse…

Q: Solve for x in the triangle. Round your answer to the nearest tenth. x = 0 24° 14

A: Here the given triangle is a right angled triangle.  So to find x we use basic trigonometric ratios.

Q: Find ? (t) that satis fies | + t?

A: NOTE: Refresh your page if you can't see any equations. . take integration  ...............(1)

Q: Solve for x. Round to the nearest tenth of a degree, if necessary. U 76 39

A: The given right triangle has UV=76, VW=39

Q: Solve for x In the triangle. Round your answer to the nearest tenth. 12 X = 34°

A:

Q: Use a calculator to solve the following equation for O on the interval [-90°, 90°]. 5 csc (0) 4 Find…

A: Use the inverse trigonometric function.

Q: Solve for x using the figure to the right. 36 4.

A: Given the right angle triangle

Q: Solve 81 3w+9, where w is a real number. Round your answer to the nearest hundredth.

A:

Q: FB A Pearson Realize Solve for a. Round to the nearest tenth of a degree, if necessary. R 84 98

A:

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 550 12

A: tan 55° = x12⇒ x = 12 tan 55°          = 12 x 1.428          = 17⇒ x = 17

Q: Solve for x in the triangle. Round your answer to the nearest tenth. 13 x = 10.8 56

A:

Q: Solve for x. Round to the nearest tenth of a degree, if necessary. 6.7 4.9

A: The triangle is solved for the angle x.

Q: 13 a Solve for all three unknowns. Only enter the answer for x here. Round to the nearest tenth.

A:

Angles in Circles

Angles within a circle are feasible to create with the help of different properties of the circle such as radii, tangents, and chords. The radius is the distance from the center of the circle to the circumference of the circle. A tangent is a line made perpendicular to the radius through its endpoint placed on the circle as well as the line drawn at right angles to a tangent across the point of contact when the circle passes through the center of the circle. The chord is a line segment with its endpoints on the circle. A secant line or secant is the infinite extension of the chord.

Arcs in Circles

A circular arc is the arc of a circle formed by two distinct points. It is a section or segment of the circumference of a circle. A straight line passing through the center connecting the two distinct ends of the arc is termed a semi-circular arc.