35 Due Thursday by 1:20pm Points 15 Submitting an external tool Section 9.1 Homework Score: 10.33/15 11/15 answered Question 12 < > Progress saved Done 810- 0/1 pt 3 2 Details Out of 600 people sampled, 270 have shopped online. Based on this, construct a 99% confidence interval for the true population proportion of people who have shopped online. Give your answers as decimals, to three places Submit Question

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​ (c) below.   TInterval ​(13.046,22.15) x=17.598 Sx=16.01712719 n=50       Question content area bottom Part 1 a. Express the confidence interval in the format that uses the​ "less than" symbol. Given that the original listed data use one decimal​ place, round the confidence interval limits accordingly.   13.0513.05 Mbps<μ<22.1522.15 Mbps ​(Round to two decimal places as​ needed.) Part 2 b. Identify the best point estimate of μ and the margin of error.   The point estimate of μ is enter your response here Mbps. ​(Round to two decimal places as​ needed.)

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​ (c) below.   TInterval ​(13.046,22.15) x=17.598 Sx=16.01712719 n=50       Question content area bottom Part 1 a. Express the confidence interval in the format that uses the​ "less than" symbol. Given that the original listed data use one decimal​ place, round the confidence interval limits accordingly.   13.0513.05 Mbps<μ<22.1522.15 Mbps ​(Round to two decimal places as​ needed.) Part 2 b. Identify the best point estimate of μ and the margin of error.   The point estimate of μ is 17.6017.60 Mbps. ​(Round to two decimal places as​ needed.) Part 3 The margin of error is E=4.554.55 Mbps. ​(Round to two decimal places as​ needed.) Part 4 c. In constructing the confidence interval estimate of μ​, why is it not necessary to confirm that the sample data appear to be from a population with a normal​ distribution?     A. Because the…

leave all answers to 3 decimals A large public opinion polling agency plans to conduct a national survey to determine the proportion of employed adults who fear losing their job within the next year. They found that 35 out of 100 randomly selected employed adults fear losing their job within the next year.  Find the 95% confidence interval (CI) estimate for the proportion of the population of employed adults who fear losing their job within the next year. CI = (Blank 1, Blank 2) blank 1? blank2?