37 Fy- 160 N 42 1.0 m 34 A uniform 15 kg pipe of length 5.0 m has a 160 N force applied 4.0 m from its lower end as shown. Using the point where the pipe touches the ground as a pivot. Calculate the sum of torques acting on the pipe.

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Chapter8: Rotational Motion
Section: Chapter Questions
Problem 85A
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37
F= 160 N
mo
42
1.0 m
34
PHYS
shown. Using the point where the pipe touches the ground as a pivot. Calculate the sum of
A uniform 15 kg pipe of length 5.0 m has a 160 N force applied 4.0 m from its lower end as
torques acting on the pipe.
Transcribed Image Text:37 F= 160 N mo 42 1.0 m 34 PHYS shown. Using the point where the pipe touches the ground as a pivot. Calculate the sum of A uniform 15 kg pipe of length 5.0 m has a 160 N force applied 4.0 m from its lower end as torques acting on the pipe.
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