Question

Asked Dec 21, 2018

Step 1

Lets assume required quantity of 10% alchol solution = x millileters

And required quantity of 50% alchol solution = y ml

Since quantity of resulting mixture = 100ml

x+y = 100 ...(1)

Quantity of alchol in x ml of 10% alchol solution = 10% of x = (x/10) ml

And quantity of alchol in y ml of 50% alchol solution = 50% of y = (5y/10) ml

Quantity of alchol in resulting mixture = 26% of 100 ml = 26 ml

Step 2

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