3.34.manufactures 37-in. high def LCD tvs in 2 separate locations, Locations I and II. The output at Location I is at most 6000 televisions/month, whereas the output at Location II is at most 5000 televisions/month. TMA is the main supplier of tvs to the Pulsar Corporation, its holding company, which has priority in having all its requirements met. In a certain month, Pulsar placed orders for 3000 and 4000 televisions to be shipped to two of its factories located in City A and City B, respectively. The shipping costs (in dollars) per television from the 2 TMA plants to the 2 Pulsar factories are as follows. To Pulsar Factories From TMACity ACity B Location I$7$3 Location II$8$9TMA will ship x televisions from Location I to city A and y televisions from Location I to city B. Find a shipping schedule that meets the requirements of both companies while keeping costs to a minimum.(x,y)=What is the minimum cost?6.Solve the linear programming problem by the method of corners.MaximizeP = x + 2y x + y ≤4 2x + y ≤7 x ≥ 0, y ≥ 0The maximum is P = at (x, y) = 7.MinimizeC = 2x + 6ysubject to x + y ≥3 x + 2y ≥5 x ≥ 0, y ≥ 0The minimum is C = at (x, y) =10.Aerobics manufactures 2 models of steppers used for aerobic exercises, x number of luxury models and y number of standard models. Manufacturing each luxury model requires 10 lb of plastic and 10 min of labor. Manufacturing each standard model requires 16 lb of plastic and 8 min of labor. The profit for each luxury model is $45, and the profit for each standard model is $30. If 6000 lb of plastic and 60 labor-hours are available for the production of the steppers per day, how many steppers of each model should Bata produce each day in order to maximize its profit?(x, y) = What is the optimal profit?$ 33.MaximizeP = 4x + 7y subject to 2x + 3y ≤ 12 x + y ≤ 5 x ≥ 0, y ≥ 0 The maximum is P = at (x, y) =4.MaximizeP = 6x + 7y subject to 2x + y ≤ 12 x − 2y ≤ 1 x ≥ 0, y ≥ 0 The maximum is P = at (x, y) 5MinimizeC = 5x + 6y subject to x + 3y ≥15 4x + y ≥16 x ≥ 0, y ≥ 0 The minimum is C = at (x, y) 6MaximizeP = 6x + 4y subject to x + 2y ≤14 x + y ≤8 2x − 3y ≥6 x ≥ 0, y ≥ 0 The maximum is P = at (x, y)7MinimizeC = 5x + 7y subject to 3x + 5y ≥ 45 3x + 10y ≥ 60 x ≥ 0, y ≥ 0 The minimum is C = at (x, y) 8Find the maximum and minimum of Q = 2x + 6y subject tox + y ≥ 4−x + y ≤ 6x + 3y ≤ 30 x ≤ 15x ≥ 0, y ≥ 0. The minimum is P = at (x, y) = 9Manufacturing has a division that produces x model A grates and y model B grates. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $1.00, and the profit for each model B grate is $3.50. Available for grate production each day are 1000 lb of cast iron and 20 labor-hours. Because of a backlog of orders for model B grates, the manager has decided to produce at least 180 model B grates per day. How many grates of each model should they produce to maximize its profits?(x, y) = What is the optimal profit?$ The maximum is P = at (x, y) =10A manufacturer of projection TVs must ship a total of at least 1000 TVs to its two central warehouses, x to the first warehouse and y to the second warehouse. Each warehouse can hold a maximum of 750 TVs. The first warehouse already has 150 TVs on hand, whereas the second has 50 TVs on hand. It costs $8 to ship a TV to the first warehouse, and it costs $18 to ship a TV to the second warehouse. How many TVs should be shipped to each warehouse to minimize cost?(x, y) = What is the minimum cost?$ 5.1Dav owns $20,000 worth of 10-year bonds of Ace Corporation. These bonds pay interest every 6 months at the rate of 2%/year (simple interest). How much income will Dav receive from this investment every 6 months?$ How much interest will Dav receive over the life of the bonds?$ 2Find the simple interest on a $1400 investment made for 5 years at an interest rate of 6%/year. What is the accumulated amount? (Round your answers to the nearest cent.)simple interest$ accumulated amount $ 3Find the effective rate corresponding to the given nominal rate. (Use a 365-day year.)4%/year compounded semiannually %/year4Find the effective rate of interest corresponding to a nominal rate of 3.8%/year compounded annually, semiannually, quarterly, and monthly. (Round your answers to two decimal places.)annually %semiannually %quarterly %monthly %5Determine the simple interest rate at which $2400 will grow to $2571 in 9 months. (Round 2 decimal places.) %/year6How many days will it take for $1900 to earn $12 interest if it is deposited in a bank paying simple interest at the rate of 4%/year? (365-day. Round nearest full day.)days

Name: 3.34.manufactures 37-in. high def LCD tvs in 2 separate locations, Loc
Uploaded: 2024-03-20T07:07:12.000Z
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Description: 3.34.manufactures 37-in. high def LCD tvs in 2 separate locations, Locations I and II. The output at Location I is at most 6000 televisions/month, whereas the output at Location II is at most 5000 televisions/month. TMA is the main supplier of tvs to

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3.34.manufactures 37-in. high def LCD tvs in 2 separate locations, Locations I and II. The output at Location I is at most 6000 televisions/month, whereas the output at Location II is at most 5000 televisions/month. TMA is the main supplier of tvs to the Pulsar Corporation, its holding company, which has priority in having all its requirements met. In a certain month, Pulsar placed orders for 3000 and 4000 televisions to be shipped to two of its factories located in City A and City B, respectively. The shipping costs (in dollars) per television from the 2 TMA plants to the 2 Pulsar factories are as follows.     To Pulsar Factories    From TMACity ACity B  Location I$7$3  Location II$8$9TMA will ship x televisions from Location I to city A and y televisions from Location I to city B. Find a shipping schedule that meets the requirements of both companies while keeping costs to a minimum.(x,y)=What is the minimum cost?6.Solve the linear programming problem by the method of corners.MaximizeP = x + 2y     x + y ≤4 2x + y ≤7 x ≥ 0, y ≥ 0The maximum is P =  at (x, y) = 7.MinimizeC = 2x + 6ysubject to  x + y ≥3 x + 2y ≥5 x ≥ 0, y ≥ 0The minimum is C =   at (x, y) =10.Aerobics manufactures 2 models of steppers used for aerobic exercises, x number of luxury models and y number of standard models. Manufacturing each luxury model requires 10 lb of plastic and 10 min of labor. Manufacturing each standard model requires 16 lb of plastic and 8 min of labor. The profit for each luxury model is $45, and the profit for each standard model is $30. If 6000 lb of plastic and 60 labor-hours are available for the production of the steppers per day, how many steppers of each model should Bata produce each day in order to maximize its profit?(x, y) =       What is the optimal profit?$ 33.MaximizeP = 4x + 7y    subject to  2x + 3y ≤ 12 x + y ≤ 5 x ≥ 0, y ≥ 0  The maximum is P =   at (x, y) =4.MaximizeP = 6x + 7y    subject to  2x + y ≤ 12 x − 2y ≤ 1 x ≥ 0, y ≥ 0  The maximum is P =  at (x, y) 5MinimizeC = 5x + 6y    subject to  x + 3y ≥15 4x + y ≥16 x ≥ 0, y ≥ 0  The minimum is C =  at (x, y) 6MaximizeP = 6x + 4y    subject to  x + 2y ≤14 x + y ≤8 2x − 3y ≥6 x ≥ 0, y ≥ 0  The maximum is P =  at (x, y)7MinimizeC = 5x + 7y    subject to  3x + 5y ≥ 45 3x + 10y ≥ 60 x ≥ 0, y ≥ 0  The minimum is C =  at (x, y) 8Find the maximum and minimum of Q = 2x + 6y subject tox + y ≥ 4−x + y ≤ 6x + 3y ≤ 30  x ≤ 15x ≥ 0, y ≥  0. The minimum is P =  at (x, y) = 9Manufacturing has a division that produces x model A grates and y model B grates. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $1.00, and the profit for each model B grate is $3.50. Available for grate production each day are 1000 lb of cast iron and 20 labor-hours. Because of a backlog of orders for model B grates, the manager has decided to produce at least 180 model B grates per day. How many grates of each model should they produce to maximize its profits?(x, y) =        What is the optimal profit?$  The maximum is P =  at (x, y) =10A manufacturer of projection TVs must ship a total of at least 1000 TVs to its two central warehouses, x to the first warehouse and y to the second warehouse. Each warehouse can hold a maximum of 750 TVs. The first warehouse already has 150 TVs on hand, whereas the second has 50 TVs on hand. It costs $8 to ship a TV to the first warehouse, and it costs $18 to ship a TV to the second warehouse. How many TVs should be shipped to each warehouse to minimize cost?(x, y) =        What is the minimum cost?$ 5.1Dav owns $20,000 worth of 10-year bonds of Ace Corporation. These bonds pay interest every 6 months at the rate of 2%/year (simple interest). How much income will Dav receive from this investment every 6 months?$ How much interest will Dav receive over the life of the bonds?$ 2Find the simple interest on a $1400 investment made for 5 years at an interest rate of 6%/year. What is the accumulated amount? (Round your answers to the nearest cent.)simple interest$ accumulated amount  $ 3Find the effective rate corresponding to the given nominal rate. (Use a 365-day year.)4%/year compounded semiannually %/year4Find the effective rate of interest corresponding to a nominal rate of 3.8%/year compounded annually, semiannually, quarterly, and monthly. (Round your answers to two decimal places.)annually     %semiannually     %quarterly     %monthly     %5Determine the simple interest rate at which $2400 will grow to $2571 in 9 months. (Round 2 decimal places.) %/year6How many days will it take for $1900 to earn $12 interest if it is deposited in a bank paying simple interest at the rate of 4%/year? (365-day. Round nearest full day.)days

Accepted Answer

We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Minimize	C = 2x + 6y
subject to	x	+	y	≥	3
	x	+	2y	≥	5
	x ≥ 0, y ≥ 0

Maximize	P = 4x + 7y
subject to	2x	+	3y	≤	12
	x	+	y	≤	5
	x ≥ 0, y ≥ 0

Maximize	P = 6x + 7y
subject to	2x	+	y	≤	12
	x	−	2y	≤	1
	x ≥ 0, y ≥ 0

Minimize	C = 5x + 6y
subject to	x	+	3y	≥	15
	4x	+	y	≥	16
	x ≥ 0, y ≥ 0

Maximize	P = 6x + 4y
subject to	x	+	2y	≤	14
	x	+	y	≤	8
	2x	−	3y	≥	6
	x ≥ 0, y ≥ 0

Minimize	C = 5x + 7y
subject to	3x	+	5y	≥	45
	3x	+	10y	≥	60
	x ≥ 0, y ≥ 0

annually	%
semiannually	%
quarterly	%
monthly	%