3NAOH(aq) + Al{NO3)s (aq) 2.1 M NAOH 1.3 g Al(NO3)a - 3NANO, + Al(OH):(aq) Volume Mass of Al(NO) Mole A(NOs) Mole NaOH NaOH 4. How is the number of moles of Al(NOala determined given its mass? A The mass (g) of Al(NOa)a is divided by its molar masn (g/mol). B. The mass (g) of Al(NO)a is added to its molar mass (g/mol). C. The mass (g) of Al(NOa)a is subtracted to its molar mass (g/mol) D. All of the above 5. How to solve for the number of molea of NaOH? A.The mans (g) of Al(NO)a is added to ita molar maas, then multiply to the molar ratio of NHOH and Al(NOla. B. The mass (g) of Al(NO)a is divided by its molar mass, then multiply to the atie of NaOH and AlINO

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Chapter14: Chemical Equilibrium
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For aumbers 4 - 6, refer to the chemical equation and dingram below for your
anawer in the following questions.
3NAOH(aq) + A{NO3) (aq) - 3NANO, + Al(OH):(aq)
2.1 M NAOH 1.3 g Al(NO3)a
Volume
Mass of Al(NO)a
Mole Al{NOs)s- Mole NaOH
→ NaOH
4. How is the number of moles of Al(NOala determined given its mass?
A. The mass (g) of Al(NOa)s is divided by its molar masn (g/mol).
B. The mass (g) of Al(NOa)a is added to its molar mass (g/mol).
C. The mass (g) of Al(NO3)a is subtracted to its molar mass
(g/mol)
D. All of the above
5. How to solve for the number of molea of NaOH?
A. The mass (g) of Al(NO)a is added to ita molar mass, then multiply to the
molar ratio of NạOH and Al(NOala.
B. The mass (g) of Al(NO)a is divided by its molar mass, then multiply to the
molar ratio of NAOH and Al(NO.la.
C. The mass (g) of Al(NOa)a is divided by its molar masa, then added to the
molar ratio of NAOH and Al(NO),
D.The molar mass of Al(NO.a)a is added to its molar mass, then added to the
molar ratio of NAOH and Al(NOala,
6. How can the volume of NaOH be determined?
A. The number of molea of NaOH is added to the molar concentration of NaOH.
11
Transcribed Image Text:For aumbers 4 - 6, refer to the chemical equation and dingram below for your anawer in the following questions. 3NAOH(aq) + A{NO3) (aq) - 3NANO, + Al(OH):(aq) 2.1 M NAOH 1.3 g Al(NO3)a Volume Mass of Al(NO)a Mole Al{NOs)s- Mole NaOH → NaOH 4. How is the number of moles of Al(NOala determined given its mass? A. The mass (g) of Al(NOa)s is divided by its molar masn (g/mol). B. The mass (g) of Al(NOa)a is added to its molar mass (g/mol). C. The mass (g) of Al(NO3)a is subtracted to its molar mass (g/mol) D. All of the above 5. How to solve for the number of molea of NaOH? A. The mass (g) of Al(NO)a is added to ita molar mass, then multiply to the molar ratio of NạOH and Al(NOala. B. The mass (g) of Al(NO)a is divided by its molar mass, then multiply to the molar ratio of NAOH and Al(NO.la. C. The mass (g) of Al(NOa)a is divided by its molar masa, then added to the molar ratio of NAOH and Al(NO), D.The molar mass of Al(NO.a)a is added to its molar mass, then added to the molar ratio of NAOH and Al(NOala, 6. How can the volume of NaOH be determined? A. The number of molea of NaOH is added to the molar concentration of NaOH. 11
B. The number of moles of NaOH is multiplied to the molar concentration of
NAOH.
C. The number of moles of Al(NOa is multiplied to the melar mass of NaOH.
2.1
IN
1.
D. The number of moles of AI(NO)s is added to the molat concentration of NaOH.
7. Which steps are helpful in solving problems on chemical reactions in
selution? L The chemical equation must be balanced.
II. Find the number of moles one mibatance.
II. Relate the number of moles te the stoichiometrically equivalent number
of moles of another subatance.
IV. Convert to the desired unit.
C. I, & III
D. I, 1I, III & IV
A1& II
B. 1, II & II
Transcribed Image Text:B. The number of moles of NaOH is multiplied to the molar concentration of NAOH. C. The number of moles of Al(NOa is multiplied to the melar mass of NaOH. 2.1 IN 1. D. The number of moles of AI(NO)s is added to the molat concentration of NaOH. 7. Which steps are helpful in solving problems on chemical reactions in selution? L The chemical equation must be balanced. II. Find the number of moles one mibatance. II. Relate the number of moles te the stoichiometrically equivalent number of moles of another subatance. IV. Convert to the desired unit. C. I, & III D. I, 1I, III & IV A1& II B. 1, II & II
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