4 5 6 7 8 9 10 422 bp 289 bp 211 bp 115 bp 11 12 13 14 15 16 17 18 19 20 422 bp 289 bp 211 bp 115 bp 23 24 25 26 27 28 29 30 422 bp 289 bp 211 bp 115 bp A. What is the arrangement of the se STSS in this individual? B. What is the linkage distance between STS-1 and STS-2? C. Could this approach to analyzing a population of sperm be applied to RFLPS? 3. 22 2. 21
Take a look at question 3 in More Genetic TIPS. Let’s suppose a
male is heterozygous for two polymorphic sequence-tagged sites.
STS-1 exists in two sizes: 211 bp and 289 bp. STS-2 also exists in
two sizes: 115 bp and 422 bp. A sample of sperm was collected
from this man, and individual sperm were placed into 30 separate
tubes. Into each of the 30 tubes were added the primers that amplify
STS-1 and STS-2, and then the samples were subjected to
PCR. The following results were obtained:
Polymerase chain reaction, or PCR , is a technique to make many copies of a specific DNA region invitro
Solution A:- One homolog contains the STS-1 that is 289 bp and STS-2 that is 422 bp, while ,while other homolog contains STS-1 that is 211 bp and STS-2 that is 115 bp. This is based on the observation that 28 of the sperm have either the 289 bp and 422 bp bands or the 211 bp and 115 bp bands.
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