4 (a) Calculate the value of Kc for the reaction: PC15 (g) PC13 Cl2 (g) + (g) AH = Positive Given that when 8.4 mol of PC15 (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PC15 (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: (i) Increasing temperature (ii) Lowering the concentration of chlorine (C12) (iii) Addition of a catalyst

Chemistry for Engineering Students
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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.98PAE
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1.4
4 (a) Calculate the value of Kc for the reaction:
PC15 (8)
PC13 (g) +
Cl2 (g)
AH = Positive
Given that when 8.4 mol of PC15 (g): is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10
dm³ container the amount of PC15 (g) at equilibrium is 7.2 mol.
Kc =
(b) Explain the effect of the following changes below on the value of Kc:
(i)
Increasing temperature
(ii)
Lowering the concentration of chlorine (C1₂)
(iii) Addition of a catalyst
Transcribed Image Text:1.4 4 (a) Calculate the value of Kc for the reaction: PC15 (8) PC13 (g) + Cl2 (g) AH = Positive Given that when 8.4 mol of PC15 (g): is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PC15 (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: (i) Increasing temperature (ii) Lowering the concentration of chlorine (C1₂) (iii) Addition of a catalyst
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