4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K, = 3 and K2 = 5. Parallel-plates have the area A = 0.7 m². The distance is d= 0.1 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (ɛ=8.85×10-12 C²/N×m²) %3D d A K2 K1 d A А AV1 AV = 24 V

4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K, = 3 and K2 = 5. Parallel-plates have the area A = 0.7 m². The distance is d= 0.1 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (ɛ=8.85×10-12 C²/N×m²) %3D d A K2 K1 d A А AV1 AV = 24 V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section16.7: Energy In A Capacitor

Problem 16.9QQ: A parallel-plate capacitor is disconnected from a batter, and the plates are pulled a small distance...

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