4) Alternatives bellowed are under consideration by a shopping mall. The interest rate is 15% per year. Which alternative should be selected on the basis of an AW analysis? Alternative First Cost ($) Annual Operating Cost ($) Salvage Value ($) Useful Life (year) X 50,000 15,000 20,000 Y 65,000 20,000 10,000 6 Z 90,000 20,000
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- Municipal Engineer wants to evaluate three alternatives for supplementing the water supply. 1st alternative – continue deep well pumping at an annual cost of $10,500 2nd alternative – install a 10” pipeline from a surface reservoir. First cost is $25,000 and annual pumping cost is $7,000 3rd alternative – install a 20” pipeline from the reservoir. First cost of $34,000 and annual pumping cost of $5,000. Life of all alternatives is 20 years. For the second and third alternatives, salvage value is 10% of first cost. With interest at 8%, which alternative should the engineer recommend? Use present worth analysis PW (deepwell) = ? PW (10”pipeline) = ? PW (20”pipeline) = ?Consider these two alternatives.Alternative A Alternative BCapital investment OMR 6000 7500Annual revenues OMR 1800 2250Annual expenses OMR 500 750Estimated market valueOMR1200 1600Useful life 10 10MARR 12% 1. Recommend which alternative should be selected.2. How much capital investment of the expensive alternative have to vary so that theinitial decision would be reversed.For these two AW relations, the breakeven point QBE in miles per year is closest to:AW1=-23,000(A/P,10%,10) + 4000(A/F,10%, 10) - 5000 - 4QBEAW2 =-8000(A/P,10%,4) - 2000 - 6QBEa. 1984b. 1224c. 1090d. 655
- ENGINNERING ECONOMICS A school building requires repainting. The surface area to be repainted is 1, 744 sq. mtrs. Two kinds of paint are available whose brands are A and B. Paint A cost ₱40 per sq. m. but needs renewal at the end of 4 yrs., while paint B cost ₱265 per sq. m. If money is worth 12% effective, how often should paint B be renewed so that it will be economical as paint A?(engineering economic) A contractor gets a large project that is expected to last for 10 years, during which the project takes a special tool that he does not have. There are two offers of tools to the contractor, both of which can meet their needs, namely: Determine which tool is more profitable to buy based on i = 15% by using: a. Annual Value Analysis with repeatability assumption b. Annual Value Analysis with the purchase price of alternative X at the time of replacement there is an increase of 20%Fitzgerald, Ivy, Garcia, Nichols, Eudy, Williams, Thomas, Owens, and Nagy (FIGNEWTON) Inc. must replace its fig - crushing equipment. The alternatives under consideration are presented below. Alternative First Cost Net Annual Benefits Useful Life A $170, 500 $14, 675 5 years B 205,000 17,000 7 years C 242,500 16, 350 8 years D 290,000 14,825 10 years a) Which anlaysis method should be used to select the alternative? b) Why should that analysis method be used? c) if FIGNEWTON uses a MARR of 8%, what alternative should be chosen? d) if FIGNEWTON uses a MARR of 18%, what alternative should be chosen? Submit one excel file with answers a), b), c) and d) highlighted clearly.
- Engineering economy - ENGR 3322 The International Parcel Service has installed a new radio frequency identification system to help reduce the number of packages that are incorrectly delivered. The capital investment in the system is $65,000, and the projected annual savings are tabled below. The system’s market value at the EOY five is negligible, and the MARR is 18% per year. Calculate the present worth of the project. a. $ 35,730 b. $ 36,730 c. $ 37,730 d. None of the choicesPlz, solve this question Economic Engineering There are two alternatives for purchasing a concrete mixer. Both the alternatives have same useful life. The cash flow details of alternative are as follows; Alternative 1: Initial Purchase Cost= Rs3,00,000, annual operating and maintenance cost = Rs20,000, Annual revenue= Rs50000, Expected salvage value = Rs125,000; useful life = 5 years. Alternative 2: Initial Purchase Cost = Rs2,00,000, annual operating and maintenance cost = Rs35,000, Annual revenue= Rs45000, Expected salvage value = Rs70,000, useful life = 5 years. Use Present Worth method to evaluate the alternatives and recommend the best option, if the rate of interest is 10% per yearA contractor has a 4-year concrete mixer whose first cost was $6,000, having 3 more years to live before being scrapped and sold at $801. Itcould now be sold for $11,922. It has an annual cost for operation and maintenance of $9,352. Its replacement is being proposed with a newmachine whose first cost will be $8,000 having a life of 9 years and salvage value $1,600. It has an operating cost of $800 per year andmaintenance cost of $320 per year. Ifthe interest is 20% cpd-a, what is the Annual Equivalent Cost of the Old Machine? 14,792
- It is proposed to place a cable on existing pole line along the shore of a lake to connect two points on opposite sides. Which is more economical? Compare alternatives using the following methods:a) ROR on Additional Investment Methodb) Annual Cost Methodc) Equivalent Uniform Annual Cost Methodd) Present Worth Cost Method Show complete manual solutionΔRoR for the first increment (Alt. C-Alt. A) is ___________________. Alt. A Alt. B Alt. C Initial cost $5,000 9,000 7,500 Annual benefits $1,457 2,518 2,133 RoR 14% 12.4% 13% Life in years 5 Group of answer choices 10.12% 11.00 11.85% 9.38%If produced by Method A, a product’s initial capital cost will be $100,000, its annual operating cost will be $20,000, and its salvage value after 3 years will be $20,000. With Method B there is a first cost of $150,000, an annual operating cost of $10,000, and a $50,000 salvage value after its 3-year life. Based on a present worth analysis at a 15% interest rate, which method should be used?