4 CH3NH2 (g) + 2 H2O (l) ➝ CO2 (g) + 3 CH4 (g) + 4 NH3 (g)     ΔHº = –138.96 kJ • Calculate the overall change in enthalpy when 30.00 grams of CH3NH2 (g) reacts with excess H2O (l).    [Be sure to include the correct sign.]

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