4) Light of wavelength 450 nm shines on a soap bubble film (n = 1.46). For what soap film thickness, other than the minimum thickness, will constructive interference occur? 5) What wavelength monochromatic source in the visible region (390 to 710 nm) can be used to constructively reflect off a soap film (n = 1.46) if the film is 214 nm thick? lambda' = lambda/n there is a shift in wavelength in thin films. You need to use lambda' and use with thickness for path difference path difference = 2t 6). Light of wavelength 418 nm is incident on a slit of width 0.35 mm, and a diffraction pattern is produced on a screen that is 2.4 m from the slit. What is the distance of the second dark fringe from the center of the bright fringe? (1 nm = 10-9 m)

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter37: Diffraction Patterns And Polarization
Section: Chapter Questions
Problem 4P: In Figure 37.7, show mathematically how many interference maxima are enclosed by the central...
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4) Light of wavelength 450 nm shines on a soap bubble film (n = 1.46). For what soap film
thickness, other than the minimum thickness, will constructive interference occur?
5) What wavelength monochromatic source in the visible region (390 to 710 nm) can be
used to
constructively reflect off a soap film (n = 1.46) if the film is 214 nm thick? lambda' =
lambda/n there is a shift in wavelength in thin films. You need to use lambda' and use with
thickness for path difference path difference = 2t
6). Light of wavelength 418 nm is incident on a slit of width 0.35 mm, and a diffraction
pattern is
produced on a screen that is 2.4 m from the slit. What is the distance of the second dark
fringe from the center of the bright fringe? (1 nm = 10-9 m)
Transcribed Image Text:4) Light of wavelength 450 nm shines on a soap bubble film (n = 1.46). For what soap film thickness, other than the minimum thickness, will constructive interference occur? 5) What wavelength monochromatic source in the visible region (390 to 710 nm) can be used to constructively reflect off a soap film (n = 1.46) if the film is 214 nm thick? lambda' = lambda/n there is a shift in wavelength in thin films. You need to use lambda' and use with thickness for path difference path difference = 2t 6). Light of wavelength 418 nm is incident on a slit of width 0.35 mm, and a diffraction pattern is produced on a screen that is 2.4 m from the slit. What is the distance of the second dark fringe from the center of the bright fringe? (1 nm = 10-9 m)
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