4. A student weighs out 1.245 grams of potassium hydrogen phthalate (molar mass 204.2 grams = 1 mole). How many moles are equivalent to this mass? 5. A student found that 22.50 mL of a 0.1850 M NaOH solution was needed for a reaction. How many moles of NaOH were needed? 6. A student titrated a potassium hydrogen phthalate sample having a mass of 1.360 grams with 19.75 milliliters of NaOH. Find the molarity of the base.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
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4. A student weighs out 1.245 grams of potassium hydrogen phthalate (molar mass 204.2 grams =
1 mole). How many moles are equivalent to this mass?
5. A student found that 22.50 mL of a 0.1850 M NaOH solution was needed for a reaction. How
many moles of NaOH were needed?
6. A student titrated a potassium hydrogen phthalate sample having a mass of 1.360 grams with
19.75 milliliters of NaOH. Find the molarity of the base.
Transcribed Image Text:4. A student weighs out 1.245 grams of potassium hydrogen phthalate (molar mass 204.2 grams = 1 mole). How many moles are equivalent to this mass? 5. A student found that 22.50 mL of a 0.1850 M NaOH solution was needed for a reaction. How many moles of NaOH were needed? 6. A student titrated a potassium hydrogen phthalate sample having a mass of 1.360 grams with 19.75 milliliters of NaOH. Find the molarity of the base.
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