8:2401:29:22 Remaining4. An object's position is describedby the following polynomial for 0 to10 s.S = 2 t^4 - 4 t^3 - 12 t^2Where s is in meters , t is inseconds , and positive is forward.a. The object's velocity function isb. The objects velocity when t = 5ism/sc The object's acceleration functionisd. The object's acceleration t= 8 ism/s^2e. The object's velocity when t =8ism/sf. Time when the object changesdirection is2 placesg. Point at which the objectchanges direction isround off to nearest ones)

Name: 8:2401:29:22 Remaining4. An object's position is describedby the foll
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Description: 8:2401:29:22 Remaining4. An object's position is describedby the following polynomial for 0 to10 s.S = 2 t^4 - 4 t^3 - 12 t^2Where s is in meters , t is inseconds , and positive is forward.a. The object's velocity function isb. The objects velocity

V= ds/dt. Differenting s with respect to time we get V=8t3-12t2-24t

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4. An object's position is described by the following polynomial for 0 to 10 s. S = 2 t^4 - 4 t^3 - 12 t^2 Where s is in meters, t is in seconds , and positive is forward. a. The object's velocity function is b. The objects velocity when t 5

4. An object's position is described by the following polynomial for 0 to 10 s. S = 2 t^4 - 4 t^3 - 12 t^2 Where s is in meters, t is in seconds , and positive is forward. a. The object's velocity function is b. The objects velocity when t 5

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter3: Two-dimensional Kinematics

Section: Chapter Questions

Problem 64PE: (a) Use the distance and velocity data in Figure 3.64 to find the rate of expansion as a function of...

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