4. Assume that a student places 1.0 mol of solid PbBr2 in 1.0 L of 0.0025 M Pb2+. Part of the lead bromide dissolves according to the following reaction PbBr2() + Pb²* (@q) + 2Br(aq) After allowing the solution to sit for 30 minutes the student determines that the bromide concentration was [Br] = 0.0010 M. What is the Pb2 concentration?

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Chapter4: Chemical Reactions
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Problem 4.81QP: A 8.50 g sample of KCl is dissolved in 66.0 mL of water. The resulting solution is then added to...
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4. Assume that a student places 1.0 mol of solid PbBr2 in 1.0 L of 0.0025 M Pb2+. Part of the lead bromide
dissolves according to the following reaction
PbBr2(0) + Pb²* (aq) + 2Br (aq)
After allowing the solution to sit for 30 minutes the student determines that the bromide concentration was
[Br] = 0.0010 M. What is the Pb2 concentration?
Transcribed Image Text:4. Assume that a student places 1.0 mol of solid PbBr2 in 1.0 L of 0.0025 M Pb2+. Part of the lead bromide dissolves according to the following reaction PbBr2(0) + Pb²* (aq) + 2Br (aq) After allowing the solution to sit for 30 minutes the student determines that the bromide concentration was [Br] = 0.0010 M. What is the Pb2 concentration?
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