4. Black body and vestigial wing in Drosophila are controlled by recessive alleles, b and vg, respectively. The dominant alleles, b* and vg*, produce wild-type flies with grey body and normal wing. A homozygous wild-type is crossed to a homozygous fly with black body and vestigial wing. The F1 progeny (all wild-type) is test-crossed. The F2 generation is as follows: 1930 wild type 1888 black, vestigial 412 black, normal 370 grey, vestigial

4. Black body and vestigial wing in Drosophila are controlled by recessive alleles, b and vg, respectively. The dominant alleles, b* and vg*, produce wild-type flies with grey body and normal wing. A homozygous wild-type is crossed to a homozygous fly with black body and vestigial wing. The F1 progeny (all wild-type) is test-crossed. The F2 generation is as follows: 1930 wild type 1888 black, vestigial 412 black, normal 370 grey, vestigial

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 26CTQ: The gene for flower position in pea plants exists as axial or terminal alleles. Given that axial is...

See similar textbooks

Similar questions

QUESTION:- In Drosophila, assume that the gene for scute bristles (s) is located at map position 0.0 and that the gene for ruby eyes (r) is at position 25.0. Both genes are located on the X chromosome and are recessive to their wild-type alleles. A cross is made between scute-bristled females and ruby-eyed males. Phenotypically wild-type F1 females were then mated to homozygous double mutant males, and 1000 offspring were produced. Give the phenotypes and frequencies expected..
mapping gene The genes for ruby eyes (rb), tan body (t) and cut wings (ct) are all found on the X-chromosome of Drosophila melanogaster. All of these are recessive traits. They map in the order rb, ct, t with 12.5 map units between rb and ct and 7.5 map units between ct and t. Suppose you cross a cut wing male with a homozygous female that is both tan and has ruby eyes. What will the F1 females look like? Draw map of the section of the X chromosomes that has these 3 genes for the F1 females Assume you testcross your F1 females. What progeny classes would you expect? ii. Give approximate numbers for each class based on a total of 2000 progeny. Assuming the i=1 and there are no double crossovers. Assuming the i=0 and there are the expected number of double crossovers.
Need help Q1: Assuming these two genes sort independently, how many progeny would you expect to show the green striped phenotype? (Enter your answers as a whole number, e.g. 1) Q2: Which of the following are recombinant phenotypes? (Select all that apply) A. Green and Spotted B. Green and Striped C. Yellow and Spotted: D. Yellow and Striped
Problem Solving: In Drosophila, the gene that controls red eye color (dominant) versus white eye color is on the X chromosomes. What are the expected phenotypic results if a heterozygous female is crossed with a white-eyed male? In cats, S = short hair; s = long hair; XC = black coat; Xc = yellow coat; XCXc = tortoiseshell (calico) coat. If a long-haired yellow male is crossed with a tortoiseshell female homozygous for short hair, what are the expected phenotypic results?
Practice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me). Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color. a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.
Question:- For a simple cross between a purple-flowered plant and a white-flowered plant, where purple is dominant over white. a. Show the F2 in a Punnett square. What are the proportions of genotypes and phenotypes? Express as fractions, decimal fractions and ratios. b. Now imagine that half of the pollen carrying the recessive allele die before reaching their target, while those carrying the dominant allele are unaffected; what are the proportions of genotypes and phenotypes now?What does this tell you about Mendel’s principle of segregation?
10. In pea plants, seed shape and seed color are controlled by genes located on different chromosomes. Seeds may be round (R) or wrinkled (r), with the allele for round seeds being dominant. Alleles for seed color are yellow and green, with the green allele (y) recessive to the yellow (Y) allele. If you cross an individual that is homozygous round and yellow with an individual that is homozygous for wrinkled and green, what is the genotype of the F1 individuals? Set up a Punnett square for the dihybrid cross.
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X chromosome alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an allele on an X chromosome, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X chromosome allele, how many types or gametes can she produce with respect to that allele?
You conduct a cross in Drosophila that produces only half as many male as female offspring. What might you suspect as a cause?
Abnormalities in the number of X chromosomes tends to have milder phenotypic effects than the same abnormalities in autosomes because of ___________ . deletions nonhomologous recombination synapsis X inactivation
The gene for flower position in pea plants exists as axial or terminal alleles. Given that axial is dominant to terminal, list all of the possible F1 and F2 genotypes and phenotypes from a cross involving parents that are homozygous for each trait. Express genotypes with conventional genetic abbreviations.
In a mating between two individuals that are heterozygous for a recessive lethal allele that is expressed in utero, what genotypic ratio (homozygous dominant: heterozygous:homozygous recessive) would you expect to observe in the offspring? a. 1:2:1 b. 3:1:1 c. 1:2:0 d. 0:2:1