5. In Drosophila flies, the allele b gives a black body, and the allele b* gives brown, the wild-type phenotype. The allele wx of a separate gene gives waxy wings, and wx" gives non-waxy. The allele cn of a third gene gives cinnabareyes, and cn* gives red. Afemale heterozygous for these three genes is testcrossed, and 700 progenies are produced which are phenotypically classified as follows: 3 b* wx* cn* 63 b wx*cn+ 25 b* wx cn* 2 b wx cn 252 b* wx* cn 33 b wx* cn 75 b* wx cn 247 b wx cn* Make a linkage map of the three genes. Compute for interference and explain what the derived value means. Show complete solutions to support your answers.

5. In Drosophila flies, the allele b gives a black body, and the allele b* gives brown, the wild-type phenotype. The allele wx of a separate gene gives waxy wings, and wx" gives non-waxy. The allele cn of a third gene gives cinnabareyes, and cn* gives red. Afemale heterozygous for these three genes is testcrossed, and 700 progenies are produced which are phenotypically classified as follows: 3 b* wx* cn* 63 b wxcn+ 25 b wx cn* 2 b wx cn 252 b* wx* cn 33 b wx* cn 75 b* wx cn 247 b wx cn* Make a linkage map of the three genes. Compute for interference and explain what the derived value means. Show complete solutions to support your answers.

Name: 5.In Drosophila flies, the allele b gives a black body, and the allel
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Description: 5.In Drosophila flies, the allele b gives a black body, and the allele b* gives brown, the wild-typephenotype. The allele wx of a separate gene gives waxy wings, and wx" gives non-waxy. The allele cn of athird gene gives cinnabareyes, and cn* gives

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 5TYK

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Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
Imagine you are performing a cross involving seed color in garden pea plants. What Fi offspring would you expect if you cross true-breeding parents with green seeds and yellow seeds? Yellow seed color is dominant over green. 100 percent yellow-green seeds 100 percent yellow seeds 50 percent yellow, 50 percent green seeds 25 percent green, 75 percent yellow seeds
In Drosophila, two genes, one for body color and one for eye color, are carried on the same chromosome. The wild-type gray body color is dominant to black body color, and wild-type red eyes are dominant to purple eyes. You make a cross between a fly with gray body and red eyes and a fly with black body and purple eyes. Among the offspring, about half have gray bodies and red eyes and half have black bodies and purple eyes. A small percentage have: (a) black bodies and red eyes; or (b) gray bodies and purple eyes. What alleles are carried together on the chromosomes in each of the flies used in the cross? What alleles are carried together on the chromosomes of the F1 flies with black bodies and red eyes, and those with gray bodies and purple eyes?
The ability of humans to taste the bitter chemical phenylthiocarbamide (PTC) is a genetic trait. People with at least one copy of the normal, dominant allele of the PTC gene can taste PTC; those who are homozygous for a mutant, recessive allele cannot taste it. Could two parents able to taste PTC have a nontaster child? Could nontaster parents have a child able to taste PTC? A pair of taster parents, both of whom had one parent able to taste PTC and one nontaster parent, are expecting their first child. What is the chance that the child will be able to taste PTC? Unable to taste PTC? Suppose the first child is a nontaster. What is the chance that their second child will also be unable to taste PTC?
Refer to problem 2. Assume a third gene has alleles C and c. For each genotype listed, what allele combinations will occur in gametes, assuming independent assortment? a. AABBCC b. AaBBcc c. AaBBCc d. AaBbCc
2.In dogs, there is a hereditary deafness caused by a recessive allele, d. A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, but the owner is unsure of the genotype. She does a testcross (crosses it to a homozygous recessive dog), and two of the five offspring are deaf. This means that the male dog A.has the genotype DD B.has the genotype Dd C.is still of unknown genotype since there were offspring of both deaf and hearing phenotypes. D.has the genotype dd
4) In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown in the image attached. a) Assign the letter “s” to the wing pattern gene and letter “w” to the background color gene. Write in the capital letter for the dominant phenotype and the lower case letter for the recessive phenotype. Also, write whether each allele is dominant (D) or recessive (R). Wing pattern gene: Spotted - letter assignment:____ - dominant or recessive:____ Striped - letter assignment:____ - dominant or recessive:____ Background color gene: orange: - letter assignment:____ - dominant or recessive:____ white: - letter assignment:____ - dominant or recessive:_____ b) Based on the four matings in Question 4: What are the genotypes of each parent in each cross? If more…
1. In Drosophila melanogaster (fruit fly) experiment, if we are going to cross male and female red-eyed fruit flies, we have the resulting offspring ratio of 50% red-eyed for female, 25 % for red-eyed male and 25% for white-eyed male. Females which are either homozygous or heterozygous for a trait still expressed eye redness whereas males can easily be affected. Why is this so? a. Females are the carriers of a gene for eye redness b. Y chromosome is responsible for red eyes in fruit flies, c. The gene for eye redness is an X-link dominant trait, d. Having a red-eyed trait is dominantly expressed by females
1.In Drosophila melanogaster body color is controlled by one gene while wing shape is controlled by a second gene. Gray body color is dominant to black body color, and normal wings are dominant to vestigial wings. Flies homozygous for gray body color and vestigial wings are crossed with flies homozygous for black body color and normal wings. A.compare the possible f2 generation genotypes and phenotypes and proportions if these two traits. B.How does your answer change if one of the original parents is homozygous for gray body color and normal wings while the other has black body color and vestigial wings?
1. A male fruit fly, heterozygous for both vestigial wings and ebony body, is crossed with a female homozygous for normal wings and heterozygous for ebony body. What fraction of their offspring will have normal wings and an ebony body?
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
3) A. How are the following proteins involved in cell division: condensing, cohesin, kinetochore complex, tubulin? B. Why does phenotype not always reveal genotype? C. How can Mendel's postulates of segregation and independent assortment be explained by meiosis? D. Explain the genotypic and phenotypic ratios predicted when performing a monohybrid and a dihybrid cross of heterozygotes? E. How can you use the product rule and sum rule to calculate the probability of a particular genotype resulting from crossing parents of specific genotypes?