4. For any angle 0, Therefore: sin (0) = cos(0 - π/2) cos(0) = sin(0 + π/2) sin(0) has a phase shift of -π/2 relative to cos(0). • cos() has a phase shift of π/2 relative to sin(0). This is not a problem, but you should try out a few values on your calcu- lator to verify this.

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Chapter2: Second-order Linear Odes
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4. For any angle 0,
Therefore:
sin(0) = cos(π/2)
cos(0) = sin(0+ π/2)
● sin(0) has a phase shift of -π/2 relative to cos(0).
●cos(0) has a phase shift of π/2 relative to sin(0).
This is not a problem, but you should try out a few values on your calcu-
lator to verify this.
Transcribed Image Text:4. For any angle 0, Therefore: sin(0) = cos(π/2) cos(0) = sin(0+ π/2) ● sin(0) has a phase shift of -π/2 relative to cos(0). ●cos(0) has a phase shift of π/2 relative to sin(0). This is not a problem, but you should try out a few values on your calcu- lator to verify this.
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