4.) How many grams of calcium carbonate will be needed to form 5.7 liters of carbon dioxide at 27 C and 760 mmHg? CaCO3(s) --> CO2(g) + CaO(s) * O 0.23 grams O 0.25 grams 23 grams O 25 grams O 100.09 grams 200.18 grams

4.) How many grams of calcium carbonate will be needed to form 5.7 liters of carbon dioxide at 27 C and 760 mmHg? CaCO3(s) --> CO2(g) + CaO(s) * O 0.23 grams O 0.25 grams 23 grams O 25 grams O 100.09 grams 200.18 grams

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter13: Gases

Section: Chapter Questions

Problem 88A

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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4.) How many grams of calcium carbonate will be needed to form 5.7
liters of carbon dioxide at 27 C and 760 mmHg? CaCO3(s) --> CO2(g) +
CaO(s) *
0.23 grams
O 0.25 grams
O 23 grams
25 grams
O 100.09 grams
O 200.18 grams

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