4. Let w(x) = |x – 4| – |x – 7|– x + 12, which can also be written as w(x) = abs(x – 4) – abs(x – 7) – x + 12. Use the procedure to find the absolute maximum and minimum values on the interval [0,8] and where they occur. The absolute value function |x| abs(x) has derivative abs' (x) = 1 for x > 0, abs'(x) = -1 for x < 0, and abs' (0) is not defined. When setting w' (x) = 0, you will be adding the numbers ±1,±1, and -1. Can they combine to give you zero?
4. Let w(x) = |x – 4| – |x – 7|– x + 12, which can also be written as w(x) = abs(x – 4) – abs(x – 7) – x + 12. Use the procedure to find the absolute maximum and minimum values on the interval [0,8] and where they occur. The absolute value function |x| abs(x) has derivative abs' (x) = 1 for x > 0, abs'(x) = -1 for x < 0, and abs' (0) is not defined. When setting w' (x) = 0, you will be adding the numbers ±1,±1, and -1. Can they combine to give you zero?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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4. Let w(x) = |x – 4| – |x – 7| – x + 12, which can also be written as w(x) = abs(x – 4) – abs(x - 7) – x + 12.
Use the procedure to find the absolute maximum and minimum values on the interval [0,8] and where they occur.
The absolute value function |x| = abs(x) has derivative abs'(x) = 1 for x > 0, abs'(x) = -1 for x < 0, and
abs' (0) is not defined. When setting w'(x) = 0, you will be adding the numbers +1,±1, and -1. Can they
combine to give you zero?
5. Let m(t) = (t + 2)2 (t – 3)4. Use the procedure to find the absolute maximum and minimum values on the interval
[-2,4] and where they occur. Suggestion: do not multiply out. Suggestion: factor the derivative completely before
setting to zero.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff41b80da-c327-4960-85a3-4b9f1b2a9a75%2Ffcd55b5e-7db0-4dfa-a8c1-56df79794146%2Faqtqifn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Page
2
of 2
4. Let w(x) = |x – 4| – |x – 7| – x + 12, which can also be written as w(x) = abs(x – 4) – abs(x - 7) – x + 12.
Use the procedure to find the absolute maximum and minimum values on the interval [0,8] and where they occur.
The absolute value function |x| = abs(x) has derivative abs'(x) = 1 for x > 0, abs'(x) = -1 for x < 0, and
abs' (0) is not defined. When setting w'(x) = 0, you will be adding the numbers +1,±1, and -1. Can they
combine to give you zero?
5. Let m(t) = (t + 2)2 (t – 3)4. Use the procedure to find the absolute maximum and minimum values on the interval
[-2,4] and where they occur. Suggestion: do not multiply out. Suggestion: factor the derivative completely before
setting to zero.
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