4. Normal yeast cells can survive on a diet of sugars, a few simple salts and one vitamin. They can make all of their amino acids and other vitamins using what can be found in their diet. You identify a mutant strain that can only survive if given alanine, which is one of the amino acids. The mutation is recessive. Based on this information, what would you predict that the normal function of the dominant allele is?

4. Normal yeast cells can survive on a diet of sugars, a few simple salts and one vitamin. They can make all of their amino acids and other vitamins using what can be found in their diet. You identify a mutant strain that can only survive if given alanine, which is one of the amino acids. The mutation is recessive. Based on this information, what would you predict that the normal function of the dominant allele is?

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Description: 4. Normal yeast cells can survive on a diet of sugars, a few simplesalts and one vitamin. They can make all of their amino acids andother vitamins using what can be found in their diet. You identify amutant strain that can only survive if given alan

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 9TYK: The ability of humans to taste the bitter chemical phenylthiocarbamide (PTC) is a genetic trait....

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Choose the statement that is incorrect. a. A son can inherit a recessive allele on an X chromosome from either parent. b. An individual may inherit three or more of each type of chromosome characteristic or the species, a condition called polyploidy. c. A female child inherits one X chromosome from her mother and one from her father. d. Pedigree analysis can be used to determine a future childs chance of being born with achcondroplasia.
The ability of humans to taste the bitter chemical phenylthiocarbamide (PTC) is a genetic trait. People with at least one copy of the normal, dominant allele of the PTC gene can taste PTC; those who are homozygous for a mutant, recessive allele cannot taste it. Could two parents able to taste PTC have a nontaster child? Could nontaster parents have a child able to taste PTC? A pair of taster parents, both of whom had one parent able to taste PTC and one nontaster parent, are expecting their first child. What is the chance that the child will be able to taste PTC? Unable to taste PTC? Suppose the first child is a nontaster. What is the chance that their second child will also be unable to taste PTC?
A recognized set of symptoms that characterize a genetic disorder is a(n) _______. a. syndrome b. disease c. abnormality d. inheritance pattern
A major difference between hereditary information in eukaryotes and prokaryotes is: a. in prokaryotes, the hereditary information is distributed among individual, linear DNA molecules in the nucleus. b. in eukaryotes, the hereditary information is encoded in a single, circular DNA molecule. c. in prokaryotes, the hereditary information is usually distributed among multiple circular DNA molecules in the cytoplasm. d. in eukaryotes, the hereditary information is distributed among individual, linear DNA molecules in the cytoplasm. e. in eukaryotes, the hereditary information is distributed amoung individual, linear DNA molecules in the nucleus.
1. a) If you were at risk of a fatal disease such as Huntington’s disease and only the 95% accurate preliminary genetic test was available, would you take the test? After all, 95% of the time the test would tell you whether you would eventually get Huntington’s disease or whether you did not have to worry about getting this disease. b) The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?
7. Why recombinant DNA is very useful in improving our health conditions?A. Human insulin can be reproduced by bacteria?B. Vaccine can be reproduced by fungi or bacteriaC. Human growth hormone can be obtained from E. ColiD. All of the above 8. Which of the following is/are example of genetic engineering?A. A farmer choose a breed of cow for greater milk production.B. The use of bacteria in order to produce human insulinC. The insertion of clone genes to plant cellsD. Cross pollination of squash flowers. 9. Bacterial cells as host organisms may expose the gene to make protein products such as insulin and growth hormone . Which of the following processes are involved?A. replication and transcription. B. Transcription and replication C. Transcription and transformation. D. Replication and transformation
2.In dogs, there is a hereditary deafness caused by a recessive allele, d. A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, but the owner is unsure of the genotype. She does a testcross (crosses it to a homozygous recessive dog), and two of the five offspring are deaf. This means that the male dog A.has the genotype DD B.has the genotype Dd C.is still of unknown genotype since there were offspring of both deaf and hearing phenotypes. D.has the genotype dd
11. Assume that a certain strain of bacteria carries a mutation that causes it to die at 42oC, but grows normally at 30oC. This allele is best described as: conditional lethal that allows survival under restrictive conditions conditional lethal that causes death under restrictive conditions recessive lethal heterogeneous
1. Every time a human cell divides, over 50 new mutations can be found in the daughter cells 2. Mutations can accumulate over the course of successive cell divisions 3. In every new kid, over 50 new mutations can be found when comparing them to their parents 4. Most of the new mutations in gametes are probably silent*, but there's a good chance that one of them might occur in a gene, and alter that gene in such a way as to potentially create a mutation *Note: by 'silent' we mean that the mutation doesn't have the potential to alter phenotype, either because it is not in a gene, or is in a gene but in the middle of an intron, or is in the coding sequence but is a silent substitution, etc., etc. 5. Most new gene mutations (i.e. mutations that occur in genes that alter gene expression, splicing or protein sequence) are recessive
5. Why is it possible for a trait that is not present in the present generation to appear in the next generation? Explain briefly.
2. What is the result of crossing over? A. recombination B. mutation C. linkage D. adaptation
6. A person is simultaneously heterozygous for two autosomal genetic traits. One is a recessive condition foralbinism (alleles A and a); this albinism gene is foundnear the centromere on the long arm of an acrocentricautosome. The other trait is the dominantly inheritedHuntington disease (alleles HD and HD+). TheHuntington gene is located near the telomere of oneof the arms of a metacentric autosome. Draw all copies of the two relevant chromosomes in this person asthey would appear during metaphase of (a) mitosis,(b) meiosis I, and (c) meiosis II. In each figure, labelthe location on every chromatid of the alleles forthese two genes, assuming that no recombinationtakes place.