answer all questions pls 4. The power dissipated in a resistance R through which is flowing a current I is equal to 1²R.Therefore, the power in a 36502 resistor carrying a current of 0.5855A is (0.5855)² (365)W.Evaluate this power and write the answer using 3 significant digits.5. The period T (time for one swing) of a simple pendulum 2.55ft long is :2.55T = 2π seconds. Evaluate T and round you answer to 3 significant digits.32.06. Write the following quantities in scientific notation. Keep the number of significantdigits same in both given number and in its scientific notation..a) 0.0000552b) 6790.007. Convert each number to standard notation.a) 1.75 x 10-5b) 9.00 x 1048. Evaluate the following expressions.a) ((3.8 -0.6) x 2) + (2.2 + 4.4)b) (((6.6+0.5) + 0.2)÷7.1)²9. How long will it take a rocket travelling at a rate of 3.2 x 106m/h to travel the 3.8 x 108 mfrom the earth to the moon? Round your answer to the nearest hour.(Hint: Distance = Rate x time)

Answered: Image /qna-images/answer/b9557596-d5af-4314-93c7-7f90af26f417.jpg

4. The power dissipated in a resistance R through which is flowing a current I is equal to 1²R. Therefore, the power in a 36502 resistor carrying a current of 0.5855A is (0.5855)²(365)W. Evaluate this power and write the answer using 3 significant digits.

4. The power dissipated in a resistance R through which is flowing a current I is equal to 1²R. Therefore, the power in a 36502 resistor carrying a current of 0.5855A is (0.5855)²(365)W. Evaluate this power and write the answer using 3 significant digits.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter30: Magnetic Fields And Forces

Section30.3: Ørsted’s Discovery

Problem 30.2CE

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