appropriate r code? 4. Use a for loop to print a list containing your name, enrollment number,state, date of birth, date of admission to vit.5. Let's consider a survey on 190 VIT students reveals the followingresults, who were asked "What's your favorite sports?"Sports:Students: 40Cricket FootballChess BasketballTennis Volleyball1530502035a. Draw a bar graph with different colors for each of the bar and alsoadd the legends for each of the bar.b. Draw a pie chart for the above data by labelling the pie chart withpercentage.

4. The current scenario here is to write the r programming code to print a list that containing the…

Answered: 4. Use a for loop to print a list…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Suppose that we are given a divisor and a target count, and we need to find the range of numbers from 1 that will have the target count of numbers divisible by the divisor. For example. If the divisor is 3 and the target count is 4, the range is 1 to 12, as in this range there are 4 numbers divisible by 3, viz. 3, 6, 9, and 12. Use a while loop to find the ending number of the range within which we will have the target count of numbers that are divisible by the divisor and print the result. Test the code with divisor = 13 and target count = 5. The printed result should be “Between 1 and 65 there are 5 numbers divisible by 13.” In rstudio
Do a trace on the for loop below, and show each iteration of the loop in the tracing table until the loop finishes. Each row in the table corresponds to one iteration of the for loop. int j=3, k=2; for(int i = 12; i >7; i--){ k = k + j - - * i ; } The tracing table is here: i i > 7 j k
In Python, using a single loop, ask user to enter values to 3 different lists, the first one should containthe names of 3 people, the second one should contain the heights of 3 people, and the third oneshould contain the weights of 3 people. Use the zip function to zip all three lists at the sametime; print list
In Python, Create 5 lists from grades = [99,87,76,54,91,65,84,69,72], one for each grade, that is, A to F. For instance, a list that holds B grades taken from the grades Panda Series would be: B = list(grades[(grades >= 80) & (grades < 90)]). Create a pie chart where the slices are the number of elements in each one of the lists of A, B, C, D, F. For colors, use r, g, b, y, m, start at 90◦, use shadow, and explode the F grades in the pie chart.
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 import java.util.Scanner; public class CourseGradePrinter {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ P.S. The answer came out wrong the first try 7 9 11 10 10 11 9 7Enter
Write a program that replaces the name of each month with its three-letter abbreviation. Save it as months.py. a) Create a list. months = ['january', 'february', 'march', 'april', 'may', 'june', 'july', 'august', 'september', 'october', 'november', 'december'] b) Use a for loop to update and store each month with its three-letter abbreviation into a new list. c) Print the value of each month in a row separated by a '|' as displayed in the output example. d) Print the new list as displayed in the output example. e) Print the original list as displayed in the output example.
How could this program work without items() or enumerate? def Find_heights(data): heights = [] for d in data: city = d[1] height = float(d[2]) index = -1 for i, item in enumerate(heights): if item[0] == city: index = i break if index == -1: heights.append([city, [height]]) else: heights[index][1].append(height) return heights height_list = Find_heights(csv_data)print(height_list)# Output: [['New York', [5.8, 5.9, 6.0]], ['Los Angeles', [5.5, 5.6, 5.7]], ['Chicago', [5.9, 6.0, 6.1]], ['Houston', [5.6, 5.7, 5.8]]] #To remove the items from the Find_average function, you can modify it to return a dictionary with city names as keys and average heights as values. Here's an updated version of the function: def Find_average(heights_list): averages = {} for city_data in heights_list: city = city_data[0] heights = city_data[1] average = sum(heights) /…
Write a program that uses a loop to ask the user to enter today’s sales for five stores. The entered results should be stored in a list. You may assume the user will enter integers. After the data has been entered, the program should display a bar graph comparing each store’s sales. Each bar should be a row of asterisks, and each asterisk representing $100 of sales (hint: there are several ways to do this. One way is to use nested loops. The outer loop iterates over the list you created and the inner loop prints one asterisk per 100 dollars of sales for that store.)
Write a program that uses a loop to ask the user to enter today’s sales for five stores. The entered results should be stored in a list. You may assume the user will enter integers. After the data has been entered, the program should display a bar graph comparing each store’s sales. Each bar should be a row of asterisks, and each asterisk representing $100 of sales (hint: there are several ways to do this. One way is to use nested loops. The outer loop iterates over the list you created and the inner loop prints one asterisk per 100 dollars of sales for that store.) A sample output: Enter today’s sales for store 1: 1000Enter today’s sales for store 2: 1200Enter today’s sales for store 3: 1800Enter today’s sales for store 4: 800Enter today’s sales for store 5: 1900SALES BAR CHART (Each * = $100)Store 1: **********Store 2: ************Store 3: ******************Store 4: ********Store 5: *******************
INPUT: Your program will read an undirected graph representation from a file called graph.txt (text file). The first line contains a number, which is the number of vertices (n). We assume the vertices are 1,2,3,…, n The second line will show 2 distinct numbers between 1 and n. After these 2 lines, there will be the edges listed in separate lines with three numbers: The first two numbers represent the edge ends (undirected graph), while the third number is the weight for that edge. For example, the graph in Figure 8.4.7 is represented as follows: 6 16 122 141 233 251 451 362 562 The program will implement the Dijkstra’s Algorithm and OUTPUT [the shortest path] and [the total weight] between the 2 vertices in line 2, e.g., for the graph above it should output: [1,4,5,6] [4]
Transcribed Image Text Implement the following to search a letter in a list. a) Create a list named vehicles: car, Truck, boat, PLANE. b) Request a user input for a search letter. c) Use the decision structure in a for loop to search all the items which contains the input letter (ignoring case) in the list. d) Print the item and its position in vehicles if it exists. Otherwise, print the statement indicating it does not contain the letter to search. e) Print the error message if more than one letter is entered. Example Output 1 Vehicles = i'car', 'Truck', 'boat', 'PLANE’] Enter a search letter: a car contains 'a' and it is in position 0. Truck does not contain 'a'. boat contains 'a' and it is in position 2. PLANE contains 'a' and it is in position 3. Example Output 2 Vehicles = ['car', 'Truck', 'boat', 'PLANE'] Enter a search letter: A car contains 'A' and it is in position 0. Truck does not contain 'A'. boat contains 'A' and it is in position 2. PLANE contains 'A' and it is in…
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1. import java.util.Scanner; public class CourseGradePrinter {public static void main (String [ ] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [ ] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ }}

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