Question help Part 1 # 4 Background:James Clerk Maxwell (1860's) can be considered the father of electromagnetics, just as Newton isconsidered the father of mechanics. Einstein adopted many ideas from Maxwell while formulatinghis theories.Maxwell wrote four governing equations in electromagnetic theory. These equations have a broadand diverse application in several phenomenon involving light, electricity, and magnetism(electromagnetism!).Objective:Examine two basic circuits: series and parallel. Examine two basic circuit components: voltagesource and resistor. Learn how to determine equivalent resistance to solve circuit problems usingOhm's Law. Calculate the electrical power, P = VI.Procedure:The simplest circuit is a voltage source (i.e. battery) and resistor. The voltage 'pushes' the currentthrough the circuit. The resistor turns some of the current into heat (or light), and thus, the voltageacross a resistor drops. This is called Ohm's Law: V = RI.RVCircuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors toone equivalent resistance. Two possible arrangements are called series, and parallel. The diagramsbelow show these arrangements, the corresponding equivalent resistances, and the main conclusionsof each arrangement.RESISTORS INEQUIVALENTRESISTANCER1SERIESVR2AAAReg = R, + R, + R,VReqR3Current is the same throughout the entire circuit. Voltage drops are not the same. PageRESISTORS INPARALLELVIR2I2R3I31111VReq%DR R, R,R,eqVoltage drops are the same throughout the entire circuit. Current is not the same.PART IFor the following problems, be sure to draw a diagram for each circuit and label all the components. Use aseparate sheet of paper.1. A5Q light bulb is connected to a 10 V battery. A) Draw a diagram of the circuit indicating current flowand voltage drops. B) Calculate the current through the light bulb.2. Power is equal to the voltage times the current, P = VI. The unit of power is the Watt, W. A) Calculatethe power used by the light bulb in Problem 1. B) Is this bulb very bright? C) What is the power usedby the light bulb if a 20 V battery was used instead (Don't forget to recalculate the current)?3. What is the equivalent resistance of two 10 2 resistors and one 5 resistor connected in A) series? B)What is the current in the circuit if the applied voltage is 50 V? C) Calculate the voltage drop acrosseach resistor. D) What is the power dissipated in each resistor?4. What is the equivalent resistance of two 10 2 resistors and one 5 2 resistor connected in A) parallel?The current is not the same throughout the circuit; however, the voltage drop across each resistor is thesame as the applied voltage. B) What is the current through each resistor if the applied voltage is 50 V?C) What is the power dissipated in each resistor? D) Is your house connected in series or parallel?PART IIFor the following problems take screenshots, paste them into ONE document, i.e. Word, and upload them toIvyLearn.1. For Problem 1 in PART I construct the circuit with an ammeter built into the circuit to show the currentand the voltmeter to show the drop in voltage across the resistor. (There is one screenshot for thisproblem.)2. For Problem 2 in PART I use the circuit that you created for Problem 1 and change the voltage to 20 V.The ammeter should show the new value of current. (There is one screenshot for this problem.)3. For Problem 3 in PART I construct the series circuit with an ammeter built into the circuit. Place theammeter after the battery. Then construct the equivalent circuit with a built-in ammeter to show that thecurrent is the same. (There are two screenshots for this problem.)4. For Problem 4 in PART II construct the parallel circuit as shown in the Circuit Construction KitTutorial. Then construct the equivalent circuit with a built-in ammeter to show that the current comingfrom the battery is the same. (There are two screenshots for this problem.)WWW

Question

Accepted Answer

Given Data:
Resistance are as follows:
R1=10 Ω
R2=10 Ω
R3=5 Ω
Applied voltage, V=50 V