4. What was the molarity of a volumetric solution of disodium edetate if 28.50 mL of the solution were consumed by 185 mg of calcium carbonate? (MW CaCO3 = 100.09 g/mole) A. 0.04 M B. 0.05 M C. 0.06 M D. 0.07 M E. None of the choices

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
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4. What was the molarity of a volumetric solution of disodium edetate if 28.50 mL of the solution were consumed by 185 mg of calcium
carbonate? (MW CaCO3 = 100.09 g/mole)
A. 0.04 M
B. 0.05 M
C. 0.06 M
D. 0.07 M
E. None of the choices
Transcribed Image Text:4. What was the molarity of a volumetric solution of disodium edetate if 28.50 mL of the solution were consumed by 185 mg of calcium carbonate? (MW CaCO3 = 100.09 g/mole) A. 0.04 M B. 0.05 M C. 0.06 M D. 0.07 M E. None of the choices
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