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4. When 1.50 g of Ba(s) is added to 100.00 g of water in a container open to the atmosphere, the reaction shown below occurs and the temperature of the resulting solution rises from 22.00°C to 33.10°C. If the specific heat of the solution is 4.18 J/(g - "C), calculate AH for the reaction, as written. Ba (s) +2 H,O (1) → Ba(OH), (aq) + H, (g) AH =?

4. When 1.50 g of Ba(s) is added to 100.00 g of water in a container open to the atmosphere, the reaction shown below occurs and the temperature of the resulting solution rises from 22.00°C to 33.10°C. If the specific heat of the solution is 4.18 J/(g - "C), calculate AH for the reaction, as written. Ba (s) +2 H,O (1) → Ba(OH), (aq) + H, (g) AH =?

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 27E: The addition of 3.15 g of Ba(OH)28H2O to a solution of 1.52 g of NH4SCN in loo g of water in a...
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4. When 1.50 g of Ba(s) is added to 100.00 g of water in a container open to the atmosphere, the reaction shown below occurs and the temperature of the resulting solution rises from 22.00°C to 33.10°C. If the specific heat of the solution is 4.18 J/(g - "C), calculate AH for the reaction, as written. Ва (6) +2 H,О () — Ba(ОН), (аg) + Н, (g) ΔΗ-? 5. What is AH for BaCO, (s) → BaO (s)+ CO, (g) Given reactions 2 Ba (s) + 0, (g) —2 ВаО (s) Ba (s) + CO, (g) + 1/2 O, (g) → BaCO, (g) AH = -1106.0 kJ AH= -822.0 kJ 82
Transcribed Image Text:4. When 1.50 g of Ba(s) is added to 100.00 g of water in a container open to the atmosphere, the reaction shown below occurs and the temperature of the resulting solution rises from 22.00°C to 33.10°C. If the specific heat of the solution is 4.18 J/(g - "C), calculate AH for the reaction, as written. Ва (6) +2 H,О () — Ba(ОН), (аg) + Н, (g) ΔΗ-? 5. What is AH for BaCO, (s) → BaO (s)+ CO, (g) Given reactions 2 Ba (s) + 0, (g) —2 ВаО (s) Ba (s) + CO, (g) + 1/2 O, (g) → BaCO, (g) AH = -1106.0 kJ AH= -822.0 kJ 82
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