# = 4.10 kg, rests on a frictionless horizontal table and is connected to a cable that passes over a pulley and is then fastened to a hanging objectAn object with mass m.1with mass m = 10.4 kg, as shown in the figureтyт2(a) Find the magnitude of the acceleration of each objectm/s2а1m/s2а2(b) Find the tension in the cableN

Question
4 views help_outlineImage Transcriptionclose= 4.10 kg, rests on a frictionless horizontal table and is connected to a cable that passes over a pulley and is then fastened to a hanging object An object with mass m. 1 with mass m = 10.4 kg, as shown in the figure тy т2 (a) Find the magnitude of the acceleration of each object m/s2 а1 m/s2 а2 (b) Find the tension in the cable N fullscreen
check_circle

Step 1

Given:

Mass of the first block, m1 = 4.10 kg

Mass of the second block, m2 = 10.4 kg

Step 2

(a) Calculating the accelerations of the blocks:

As both blocks are tied with the same strong inextensible string, so acceleration of both the blocks would be the same. Let’s assume acceleration of the blocks is ‘a’ as shown. help_outlineImage Transcriptioncloseа mg FBDs of both the blocks are shown in the above figure Writing equarions for both the blocks, T ma (For block 1)..) (2) mg-T=m,a (For block 2) Solving equations 1 and 2, m,g-ma m,a mg (my+ m Or a= (3) Substituing the values of masses and gravity (10.4kg)(9.8m/s) (4.10kg +10.4kg) = 7.03m/s a= Hence, acceleration of block 1, a a 7mls (Towards right side) And acceleration of block 2, a, a=7m/s (Downward) fullscreen
Step 3

(b) Calculating the tensi... help_outlineImage TranscriptioncloseSubsituting the value of acceleration from equation 3 into equation 1 -6 т,g uш т +m, T m т +m, Substituting the values of masses and gravity (4.10kg)(10.4kg) T = x 9.8m/s2 = 28.82N 4.10kg+10.4kg T 28.82N fullscreen

### Want to see the full answer?

See Solution

#### Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

### Newtons Laws of Motion 