400 N 600 N 1 m 1 m - 2 m- A B 600 N.m 1.5 m
Q: 0.8 1 0.8 m 0.8 m D 0.6 m E 1.2 m 1.2 m y F 1.2 m
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Q: 20 KN/m 10 KN/m 學 2.00 1.70 1.30
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Q: 20 Ibf 200 kg 250 20 kN m A 2 FT 200 kg
A: Find the resultant force at point C in N
Q: 20 KN 10 KN 10KN/m 15KN/m 10 KN/m B. 1.00 1.00 2.00 1.00
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Q: س )1( : اذا كانت منظومة القوى المبينة بالشكل )1( 60 هي منظومة متزنة ، احسب القوة T والزاوية 0 20 lb…
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Q: 300 N -1.35 m. -1.35 m 1.2m 1.5m 300 N 552 N 500 N
A: For solution refer below images.
Q: 500 N/m 1.5b- - 2 m – 2 m
A: A beam is defined as a structural member subjected to transverse shear load during its…
Q: 20 N/m KAC www !3! 3 m
A: given:
Q: 2 (1, 1) m A
A: GivenF→=-2xyi→-3y2j→displacment vector 1-2d→=xi→+yj→
Q: -20KN/m 10kN/m 2 m -5kN 3 m A B 2 m 2 m
A: Data given - Two udl of 20 kN/m & 10 kN/m
Q: F B A 6 m 4m 4m
A: A beam is defined as a structural member subjected to transverse shear load during its…
Q: B E 200 N 1 m A D -1 m 1 m 2 m 800 N m
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Q: 400 N 3 m A, 8 m 4 m D 1200 N
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Q: 20 sq mm 40 sq mm 10° W W= 40 kg stress AB = Stress AC
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Q: 500 N/m 1.5 b В + x m 2 m 2 m
A: to find : Reaction Force at B (RB) =?
Q: 2. A MATHaling.com Ax 2 m 2 m C 2 m 200 N 100 N Ay Figure 1:
A: For solution refer below images.
Q: 1.5 m 1.5 m P. 180 kg
A: For solution refer below images.
Q: FA- 450 N 0.4 m 0.3 m A 450 N
A: Given that, Couple force=450 N, Write the co-ordinate of the vector as follows, A≡0,0,0.3B≡0.4,0,0.3…
Q: 3.32 10 KN 2m C 2.5 m 2. 1.33m
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Q: 2. 900N 480 N 4 m A 4m 13 2m C 4 m 4 m - 900ル ー1380N
A: Objective: To draw the moment and load diagram of the given shear force diagram.
Q: B 0.75 m 1.5 m 2 m A = 300 mm? A = 250 mm2 A = 5 mm D E = 200 GPa
A: Given,
Q: 30 EN 100 kN.m M-1200 KN m 2 m 3m 4 m 5m
A: Given: To draw SFD and BMD to calculate shear force and bending moment.
Q: Im 35 N/m 2m 30 N Im в 85 N 100 N.m 60 2m 2m 0.5m 1.5 m
A: Mechanical Equilibrium: A body is said to be in mechanical equilibrium if it satisfies the following…
Q: 3 m 3 m 3 m E C 12 M= 59 N.M 13 3 4 50N D
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Q: Datum x(t) 2 m k = 2U00 N/m m; = 5S kg 3 т m; = 1T kg Figure Q2
A: Given: m1=52 kgm2=10 kgk= 2000 N/mg=9.81 m/s2
Q: 2 m. 2 m. B cable 0=60° w =30 kN bar B
A: Concept Of Mechanics Used.
Q: 400 N/m
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Q: k=2 x 10° N/m ITTTTITTT m = 4.2 kg 10 cm 40 cm 60 cm
A: For solution refer below.
Q: 1 m 1 m 30° b. 0.5 m 0.5 m b 1m -75 mm-
A: Given Data The mass of the drum is:m=20 kg The supported diamter of frame is :D=2mm Now draw the…
Q: (A) 99 MN/m^2 (B) 53 MN/m^2 at right angles to (a).
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Q: C cord 2m 1.5m 10 N B. 56 N.m 2.5m E- 0.25m F 3m 1.5m 3m
A: Find the reactions at point B on member ABC
Q: 6 m 6 m 4 m A
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Q: 29.20 kg, 4220.29 N
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Q: 8 KN 3 AN/m 12 AN 6 KN/m BC D 2.0 m 1.0m 3.0 m 3.0 m
A: Apply the equilibrium condition of force in the vertical direction. Apply the equilibrium condition…
Q: 6500 N - 4.5 m– 4.5 m A 1.5 m D 2 m E B
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Q: Water 2 m A B 0.6
A: The vertical force on the curve surface can be determined by calculating the weight of the fluid…
Q: 1- A fluid is one which can be defined as a substance a) Has some shear stress at all points. b) Can…
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Q: 650 N 350 N 125 N/m 12m 18m 2m 2m 2m
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Q: V3 Az = 0.07 m² (3)| V2 P2 = 350 kPa A2 = 0.02 m² (2) (1) V1 = 4 m/s P1 = 400 kPa A1 = 0.1 m²
A: Given data: The flow rate through pipes 1, 2, and 3 is Q1, Q2, and Q3 respectively.Q1=Q2+Q3 The…
Q: P=300 N 3 m 700 N.M 800 N.M 900 N.M
A: Moment is the rotational effect causes by force. Moment is the product of force and perpendicular…
Q: 400 lb F1 = 400 F2 = -600 k F3 = 500 sin 45 i-s00 cos 45k 7t Y600 lb 45 M- rxF,. M,- r2x , M,- rgxf,…
A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: 1000 kg. 400 kg D BV 3m 1.5m * 1.5m 6m R R2
A:
Q: A cubic meter of a liquid has a weight of 9800 N at a location where g = 9.79 m/s2. What is its…
A: Data given- W = 9800 N g = 9.79 m/s2 If g' = 9.83 m/s2 Then W' = ?
Q: 600 N 300 300 F E 120 N-m 60° 60 G 200 400 200
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Q: 3 10⁰ 100kg/ 25° Ms = 0.3 hk = 0.2 =
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Q: 2.6 kN 2.4 kN-m B A 1.0 m 1.0 m 1.0 m
A: To draw the shear force or bending moment diagram, one should first determine the reaction at the…
Q: 1.5 m B 1.5 m 1 m F- 560 N 3 m A 3 m Fig. 2.1
A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…
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- The figure shows a three-pin arch. Determine the horizontal component of the pin reaction at A caused by the applied force P.The cable of the suspension bridge spans L=140m with a sag H=20m. The cable supports a uniformly distributed load of w0 N/m along the horizontal. If the maximum allowable force in the cable is 4 MN, determine the largest permissible value of w0.Draw the FBD of the entire frame, assuming that friction and the weights of the members are negligible. How many unknowns appear on this FBD?
- Member AB (helical spring) and Member AC (axial rod) are carrying a weight at point A. Member AB has the following properties: R = 90 mm, n =4 turns, G = 70 GPa, d = 30 mm, and allow = 105 MPa while Member AC has the following properties: L = 2 , A = 500 mm2, E = 200 GPa, and allow = 30 MPa. Determine the maximum safe value of W (in N). Use simplified formula for the helical spring.The simplest truss consists of two rods and is loaded by the force F. Given: F = 5,1 kN. Angle α = 69 degrees. Find: the algebraic (positive or negative) value (in kN) of normal force N1 in the rod 1, considering that N1>0 for tension and N1<0 for compression.To determine the reaction forces at supports on a horizontal beam by using the equations of equilibrium for a static application. As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a=2.0a=2.0 ftft, b=7.0b=7.0 ftft, and c=12.0c=12.0 ftft. The applied forces are F1=1.50F1=1.50 kipkip and F2=2.00F2=2.00 kipkip. Force F1F1 is applied at an angle θ=60∘θ=60∘ with the horizontal. Neglect the weight of the beam.(Figure 1)
- Find the support reacions and joint force of the construction shown on the figure, if; P=12 kN q=9 kN/m M=12 kN and L=2 mP1=215 N P2=325 N P3=150 N L1=3m L2=4m 1. Draw a "free body diagram". The diagram should be for members BE, BF, CF, and DF to help solve. 2. What is the force on members CF, BF, BE? Is each of these members having tension or compression?Statics-Two Force Members 1. Determine the force P required to maintain equilibrium of the pulley system, and the reactions at the ceiling. 2. Assume W=1.25kN 3. Show and clearly label all Free Body Diagram to determine solution.
- The simplest truss consists of two rods and is loaded by the block. Given: block weight Q = 9,4 kN. Angle α = 31 degrees. Find: the algebraic (positive or negative) value (in kN) of normal force N1 in the rod 1, considering that N1>0 for tension and N1<0 for compression.Q/ Find the reaction forces at A and B, (A pin connection and B roller connection)? 120N/m....An electric motor drives a compressor by use of V-belt. The angle of contact on the smaller pulley is 2.89 rad and the belt speed runs at 29.36 m/s. The groove angle of the pulleys is 35°. Determine the tension in the slack side of the belt in N if the belt has a cross-sectional area of 366 mm2, density 1000 kg/m3, and an allowable tensile stress of 2.3 MPa. The coefficient of friction between the belt and the pulley is 0.3