IR Spectrum (liquid film) 4000 100 80 Lalalalalalala % of base peak 3000 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) 80 91 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 120 v (cm¹) m/e 160 ww 1600 1200 800 0.0 Mass Spectrum 0.5 C₂H,Br 280 7 M+ 170/172 160 200 120 6 240 expansion 140 expansion 140 5 solvent 130 130 80 4 1.0 1.5 absorbance Problem 24 UV spectrum 0917 mg/10 mis path length: 0.20 cm solvent hexane 300 200 ppm ppm 3 40 250 λ (nm) 2 0 1 350 8 (ppm) TMS L 1 0 8 (ppm)
IR Spectrum (liquid film) 4000 100 80 Lalalalalalala % of base peak 3000 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) 80 91 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 120 v (cm¹) m/e 160 ww 1600 1200 800 0.0 Mass Spectrum 0.5 C₂H,Br 280 7 M+ 170/172 160 200 120 6 240 expansion 140 expansion 140 5 solvent 130 130 80 4 1.0 1.5 absorbance Problem 24 UV spectrum 0917 mg/10 mis path length: 0.20 cm solvent hexane 300 200 ppm ppm 3 40 250 λ (nm) 2 0 1 350 8 (ppm) TMS L 1 0 8 (ppm)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
What is the IR and HNMRAndCNMR and mass in this example
Transcribed Image Text:L
4000
100
80
IR Spectrum
(liquid film)
60
40
20
% of base peak
3000
سطا
40
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
80
91
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
10
9
8
2000
120
v (cm¹)
m/e
160
TW
1600
1200
7
M**
170/172
160
200
120
6
Mass Spectrum
800 0.0F
0.5
1.0
1.5
240
expansion
140
expansion
140
5
C₂H,Br
280
solvent
130
130
80
4
-
absorbance
Problem 24
UV spectrum
0917 mg/10 mis
path length: 0.20 cm
solvent hexane
200
ppm
ppm
3
40
250
300
λ (nm)
2
0
1
350
8 (ppm)
TMS
L
0
8 (ppm)
113
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