What is the IR and HNMRAndCNMR and mass W hmmmmIR Spectrum(liquid film)337640003000200012008001600v (cm¹)Mass Spectrum1008040% of base peakM-88 (<1%)80 120 160m/e4013C NMR Spectrum(50.0 MHz, CDCI, solution)162DEPT CH, CH, CHproton decoupled200¹H NMR Spectrum(200 MHz, CDCI, solution)1098160720012062405CH₁20280solventa804Problem 73No significant UVabsorption above 220 nm40Exchanges withD₂0I3208 (ppm)TMS1108 (ppm)

The Proton NMR shows us the no of different types of hydrogens present in the given organic…

4000 100 во % of base peak 3376 3000 59 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDC, solution) 80 IR Spectrum (quid film) 2000 M-88 (<1%) 120 160 m/e DEPT CH, CH, CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 v (cm¹) 160 www 1600 1200 7 200 240 120 800 Mass Spectrum 6 5 CH₁20 280 solvent 80 Problem 73 No significant UV absorption above 220 nm 40 Exchanges with D₂0 I 3 2 08 (ppm) TMS 0 8 (ppm) 1

4000 100 во % of base peak 3376 3000 59 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDC, solution) 80 IR Spectrum (quid film) 2000 M-88 (<1%) 120 160 m/e DEPT CH, CH, CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 v (cm¹) 160 www 1600 1200 7 200 240 120 800 Mass Spectrum 6 5 CH₁20 280 solvent 80 Problem 73 No significant UV absorption above 220 nm 40 Exchanges with D₂0 I 3 2 08 (ppm) TMS 0 8 (ppm) 1

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter20: Molecular Mass Spectrometry

Section: Chapter Questions

Problem 20.11QAP

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MS: m/z=148 (M,100%),149 (11%) IR (liquid film): 3077‐2835 (multitude of weak peaks) 1640(m),1611(m),1511(s),1301(m),1247(s),1176(s),1038(s),922(m),914(m) and 810(m)cm^-1 There are no absorptions in the 3100-‐4000cm^-1 region of the spectrum. (m=medium absorption, s=strong absorption). Choose (circle) the best structure for estragole (W) from the four possible structures (1-4)shown below. Explain briefly how you eliminated each of the incorrect structures for W.
what is the purpose y the result of Spectrophotometric of a Cobalt Chloride Solution Analysis? Table 1 Absorption Spectrum of Cobalt Chloride Using a Spectrophotometer Wavelength Absorbance 400 410 420 430 440 450 460 370 480 490 500 510 520 530 540 550 560 570 580 590 600 610 620 630 640 650 660 670 680 690 700 0.036 0.044 0.063 0.095 0.147 0.215 0.284 0.329 0.362 0.402 0.450 0.479 0.464 0.398 0.314 0.216 0.142 0.087 0.054 0.041 0.036 0.036 0.034 0.028 0.030 0.023 0.023 0.023 0.014 0.014 0.011 Test Tube Number Cobalt Chloride Concentration (mol/mL) Absorbance at 510 nm 1 0.000 0.000 2 0.009 0.042 3 0.018 0.92 4 0.027 0.139 5 6 0.036 0.045 0.190 0.236 7 (Unknown) 0.151
For each set of spectral data, propose an acceptable structure that is consistent with that data 1.. MS: M+ m/z= 84, IR: 2960, 2870, 1734 cm^-1, 13C NMR: 220.16 (C), 38.30 (CH2), 23.24 (CH2) ppm 2. MS:M+ m/z= 138, (M:M+2=1:1), IR: ~3010(broad), 1715 cm^-1, 13C NMR: 173.61(s), 25.21(t) ppm 3. MS:M+ m/z=88, IR: 2960, 2870, 1736cm^-1, 13C NMR: 170.95 (C), 60.34 (CH2), 20.98 (CH3), 14.23 (CH3) ppm 4. MS: M+ m/z=73, IR: 3410, 2960, 2870, 1668 cm^-1, 13C NMR: 171.27 (C), 26.26 (CH3), 22.87 (CH3) ppm
1. For each set of spectral data, propose an acceptable structure that is consistent with the data. a. MS: M+ m/z=71, IR: 3340, 2960, 2870 cm-1 , 13C NMR: 47.20 (CH2), 25.64 (CH2) ppm b. MS: M+ m/z= 102, IR: 2960, 2870 cm-1, 13C NMR: 72.73 (t), 23.20 (t), 10.80 (q) ppm c. MS: M+ m/z=74, IR: 3310, 2960, 2870 cm^-1, 13C NMR: 62.44 (down), 34.86 (down), 18.98 (down), 13.88 (up) ppm (DEPT-direction) d. MS: M+ m/z=92 (M:M+2=3:1), IR: 2960, 2870 cm^-1, 13C NMR: 67.29 (C), 34.46 (CH3) ppm e. MS:M+ m/z=70, IR: 3070, 2960, 2870, 1666 cm^-1, 13C NMR: 138.92 (t), 114.26 (d), 35.96 (t), 22.17 (t), 13.59 (q) ppm f. MS: M+ m/z= 72, IR: 2960, 2870 cm^-1, 13C NMR: 31.68 (t), 29.80 (d), 22.20 (q), 11.69 (q) ppm g. MS: M+ m/z= 84, IR: 2960, 2870, 1734 cm^-1, 13C NMR: 220.16 (C), 38.30 (CH2), 23.24 (CH2) ppm h. MS:M+ m/z= 138, (M:M+2=1:1), IR: ~3010(broad), 1715 cm^-1, 13C NMR: 173.61(s), 25.21(t) ppm i. MS:M+ m/z=88, IR: 2960, 2870, 1736cm^-1, 13C NMR: 170.95 (C), 60.34 (CH2), 20.98 (CH3), 14.23 (CH3)…
The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 and are found in the accompanying file. The 1H are also listedbelow. Identify the name of compound 1 and Provide a full analysis of the NMR spectra for compound 1 with table showing peak name and assignment 1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).
A H1 NMR signal is observed at 117.0 Hz (downfield of TMS) on a 1.20×102‑MHz instrument. a) What is the observed chemical shift in parts per million (ppm)? Chemical shift is ppm b) What is the chemical shift, in parts per million (ppm), if the sample is analyzed with a 60.0‑MHz instrument? Chemical shift is ppm c) Where will the proton signal appear, in hertz, if the sample is analyzed with a 60.0‑MHz instrument?
For each set of spectral data, propose an acceptable structure that is consistent with the data 1.. MS: M+ m/z=92 (M:M+2=3:1), IR: 2960, 2870 cm^-1, 13C NMR: 67.29 (C), 34.46 (CH3) ppm 2.. MS:M+ m/z=70, IR: 3070, 2960, 2870, 1666 cm^-1, 13C NMR: 138.92 (t), 114.26 (d), 35.96 (t), 22.17 (t), 13.59 (q) ppm 3.. MS: M+ m/z= 72, IR: 2960, 2870 cm^-1, 13C NMR: 31.68 (t), 29.80 (d), 22.20 (q), 11.69 (q) ppm
plese don't handwritten solution... What MS resolving power is needed to fully resolve the C8H8NO2 and C7H6N2O2 ions (at the base peaks)?
Spectrophotometric of a Cobalt Chloride Solution Analysis 1. explain in detail the results of this experiment Table 1 Absorption Spectrum of Cobalt Chloride Using a Spectrophotometer Wavelength Absorbance 400 410 420 430 440 450 460 370 480 490 500 510 520 530 540 550 560 570 580 590 600 610 620 630 640 650 660 670 680 690 700 0.036 0.044 0.063 0.095 0.147 0.215 0.284 0.329 0.362 0.402 0.450 0.479 0.464 0.398 0.314 0.216 0.142 0.087 0.054 0.041 0.036 0.036 0.034 0.028 0.030 0.023 0.023 0.023 0.014 0.014 0.011 Test Tube Number Cobalt Chloride Concentration (mol/mL) Absorbance at 510 nm 1 0.000 0.000 2 0.009 0.042 3 0.018 0.92 4 0.027 0.139 5 6 0.036 0.045 0.190 0.236 7 (Unknown) 0.151 Results
Calculate the concentration of a solution of peptide AWSME, in mM if the absorbance at 280 nm for the solution is 0.6 absorbance units, and a 0.2-cm cuvette is used. For the extinction coefficient, take into account that e280(Trp) = 5690 M-1 cm-1 and e280(Tyr) = 1280 M-1 cm-1. Round your answer to two decimals.
if a 1.32 * 10^-4 M stock of dye had a maximum absorbance of 0.900 at 600 nm what is the extinction coefficient of this dye? go into as much detail as possible please (this is all the information i was given.)
Calculate the HDI of each FM and propose 2structures for two molecules that are isomers.Specify what the indicated absorption (s) shouldbe to.a.C7H15NO with strong absorptions in 3400, 3270and 1670, 1390, and 1370 cm-1b. C6H10O with absorptions in 2065 (m), 1685 (f),1650 (m) and 970 (f) cm-1c. C9H12O, with absorptions in 1600 and 1500 and1245 cm-1.